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pashok25 [27]
3 years ago
13

Select all of the ordered pairs that make the inequality y > x2 + 3x – 4 true. (0, 0) (2, 1) (–2, –1) (–5, –1)

Mathematics
1 answer:
fredd [130]3 years ago
8 0
The correct answers are:
___________________________________________________
   [A]:   " (0, 0) " ;   <u>AND</u>:
___________________________________________________
   [C]:  " (-2, -1) " .
___________________________________________________

Explanation:
___________________________________________________

[A]:  " (0, 0) " ;  is correct; 

Since, when "x = 0"  and y = 0 : 

"0 <span> > - 4 " ; which is correct.
</span>___________________________________________________
  [B]:  "(2, 1)" is incorrect,  since:

when "x = 2" and "y = 1" ; 

" 1 > 6"  ; is incorrect.
___________________________________________________
[C]:  "(-2, -1)" ; is correct;

Since, when "x = -2" and y = -1" ; then:

   "-2 <span> > -6 ; which is correct.
</span>___________________________________________________
[D]:  " (-5, -1) " ;  is INCORRECT.

 since when "x = -5" and "y = -1 ;

then:  -1 > 6 ; which is INCORRECT. 
___________________________________________________
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Answer:

30 degrees

Step-by-step explanation:

u dot v=1*4+1*4+1*4+0*4=4+4+4+0=12

|u|=sqrt(1^2+1^2+1^2+0^2)=sqrt(3)

|v|=sqrt(4^2+4^2+4^2+4^2)=sqrt(4*4^2)=2*4=8

cos(theta)=u dot v/(|u||v|)

cos(theta)=12/(sqrt(3)*8)

cos(theta)=3/(sqrt(3)*2)

cos(theta)=sqrt(3)/2

theta=30 degrees

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