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VMariaS [17]
3 years ago
7

Simply (a8a6)^(1/7)/a2

Mathematics
1 answer:
boyakko [2]3 years ago
6 0
I got the answer 1.. hope it works!
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What is<br> is 1/4 + 9/10y -3/5y +7/8 written in simplest form?
Leviafan [203]

Answer:

Step-by-step explanation:

\frac{1}{4}+\frac{9}{10}y - \frac{3}{5}y+\frac{7}{8}\\\\=\frac{1}{4}+\frac{7}{8}+\frac{9}{10}y-\frac{3}{5}y\\\\

Combine like terms. 1/4 and 7/8 are like terms and LCD of 4 and 8 is 8

9/10y and -3/5y are like terms and LCD of 10 , 5 is 10

= \frac{1*2}{4*2}+\frac{7}{8}+\frac{9}{10}y-\frac{3*2}{5*2}y\\\\=\frac{2}{8}+\frac{7}{8}+\frac{9}{10}y-\frac{6}{10}y\\\\=\frac{9}{8}+\frac{3}{10}y

5 0
3 years ago
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your sister can get $30 per day for selling clothes at the market. but she has to $60 at first for renting a stand. you can get
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3 30 60
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6 120 120

So day 6.
8 0
3 years ago
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PLEASEE HELP!!!!!!!!!!! <br> QUESTION IS IN THE IMAGE
Lena [83]
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4 0
2 years ago
Which operation results in a binomial? (3y ^ 6 + 4) (9y ^ 12 - 12y ^ 6 + 16)
AleksAgata [21]

Step-by-step explanation:

Given the expression, (3y ^ 6 + 4)  (9y ^ {12} - 12y ^ 6 + 16), we want to know which sign placed in between the two polynomial will produce a binomial.

Using a plus (+) sign to check:

= (3y ^ 6 + 4) + (9y ^ {12} - 12y ^ 6 + 16)\\=  (3y ^ 6 + 4) + (9y ^ {12} - 12y ^ 6 + 16)\\collect \ like \ terms\\= 9y^{12} +3y^6 - 12y^6 + 16+ 4\\= 9y^{12} - 9y^6 + 20\\

From the gotten value, it can be seen that the resulting answer produces 3 terms, showing that it results in a trinomial instead of binomial.

Using a plus (-) sign to check:

= (3y ^ 6 + 4) - (9y ^ {12} - 12y ^ 6 + 16)\\=  3y ^ 6 + 4 - 9y ^ {12} + 12y ^ 6 - 16\\collect \ like \ terms\\= -9y^{12} +3y^6 +12y^6 + 4-16\\= -9y^{12} +15y^6 -12\\

From the gotten value, it can be seen that the resulting answer produces 3 terms, showing that it results in a trinomial instead of binomial.

<em>Hence none of the operations given results in a binomial</em>

3 0
3 years ago
1 1/3 divided by 1 3/4
Lina20 [59]

Answer:

11.895

Step-by-step explanation:

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3 years ago
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