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Irina-Kira [14]
3 years ago
7

Determine the range of the function.

Mathematics
1 answer:
HACTEHA [7]3 years ago
5 0
Answer is A all real numbers
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The volume of a cube depends on the length of its sides. This can be written
White raven [17]

Answer:

Step-by-step explanation:

The given question is that the volume of a cube depends on the length of its sides.This can be written in function notation  as v(s). What is the best interpretation of v(3)=27.

Solution:

According to the question the volume of a cube depends on the length of its sides. According to the statement we will apply the formula of volume of a cube.

V(s)=s³

In this question we have given s=3ft.

So, we will put the value of 's' in the formula.

V(s)=s³

V(3)=3³

Multiply 3 three times to get the answer.

V(3)=3*3*3

V(3)=27 ft³

This means that the cube has a volume of 27ft³ with the length of its sides 3ft....

8 0
4 years ago
<img src="https://tex.z-dn.net/?f=%5Csf%20%5Clim_%7Bx%20%5Cto%20%5Cinfty%7D%20%5Ccfrac%7B%5Csqrt%7Bx-1%7D-2x%20%7D%7Bx-7%7D" id=
BARSIC [14]
<h3>Answer:  -2</h3>

======================================================

Work Shown:

\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{x-1}-2x }{ x-7 }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \frac{1}{x}\left(\sqrt{x-1}-2x\right) }{ \frac{1}{x}\left(x-7\right) }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \frac{1}{x}*\sqrt{x-1}-\frac{1}{x}*2x }{ \frac{1}{x}*x-\frac{1}{x}*7 }\\\\\\

\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{\frac{1}{x^2}}*\sqrt{x-1}-2 }{ 1-\frac{7}{x} }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{\frac{1}{x^2}*(x-1)}-2 }{ 1-\frac{7}{x} }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{\frac{1}{x}-\frac{1}{x^2}}-2 }{ 1-\frac{7}{x} }\\\\\\\displaystyle L = \frac{ \sqrt{0-0}-2 }{ 1-0 }\\\\\\\displaystyle L = \frac{-2}{1}\\\\\\\displaystyle L = -2\\\\\\

-------------------

Explanation:

In the second step, I multiplied top and bottom by 1/x. This divides every term by x. Doing this leaves us with various inner fractions that have the variable in the denominator. Those inner fractions approach 0 as x approaches infinity.

I'm using the rule that

\displaystyle \lim_{x\to\infty} \frac{1}{x^k} = 0\\\\\\

where k is some positive real number constant.

Using that rule will simplify the expression greatly to leave us with -2/1 or simply -2 as the answer.

In a sense, the leading terms of the numerator and denominator are -2x and x respectively. They are the largest terms for each, so to speak. As x gets larger, the influence that -2x and x have will greatly diminish the influence of the other terms.

This effectively means,

\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{x-1}-2x }{ x-7 } = \lim_{x\to\infty} \frac{ -2x }{ x} = -2\\\\\\

I recommend making a table of values to see what's going on. Or you can graph the given function to see that it slowly approaches y = -2. Keep in mind that it won't actually reach y = -2 itself.

5 0
3 years ago
A random sample of 20 houses selected from a city showed that the mean size of these houses is 1880 square feet with a standard
azamat

Answer:

Option C

Step-by-step explanation:

Given that for a  random sample of 20 houses selected from a city showed that the mean size of these houses is 1880 square feet with a standard deviation of 320 square feet.

X, the sizes of houses is Normal

Hence sample mean will be normal with

Mean = 1880

and std dev = \frac{320}{\sqrt{20} } \\=71.5542

For 90% confidence interval critical value for t with degree of freedom 19 is

1.328

Confidence interval upper bound

= mean + margin of error

= 1880+1.328*71.55\\=1975

Option C is right

3 0
3 years ago
You have 25% of the tickets required for a souvenir. What fraction of the required tickets do you have?
lidiya [134]
25% is 1/4

45x1.07 is 48.15
(Convert percent to decimal and add one bc it’s increasing each month. Multiply it by the original cost to get the new cost)
7 0
3 years ago
Read 2 more answers
Please help will give brainliest
almond37 [142]

Step-by-step explanation:

\frac{32.5}{33.8}  = 0.9615

5 0
3 years ago
Read 2 more answers
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