Let me = slope
m = (18 - (-2))/(4 - 0)
m = 20/4
m = 5
We now plug slope 5 and one of the given points into the point-slope formula.
y - y_1 = m(x - x_1)
y - 18 = 5(x - 4)
y - 18 = 5x - 20
y = 5x - 20 + 18
y = 5x - 2
Done!
<span>The sum of angles CAD and DAB is 180 degrees. This is because they are all on a straight line (because points CAB are colinear) and angles on a straight line add up to 180 degrees.</span>
f(x) = 2(x^2 + 14x + ) - 5 2 is taken out of first 2 terms.
f(x) = 2(x^2 + 14x + (14/2)^2 ) - 5 - 2(14/2)^2
<em><u>2 steps </u></em>
- Inside the brackets: Linear term's coefficient (14) divided by 2 and squared
- Outside the brackets: (14/2)^2 multiplied by 2 and subtract so that there is no change in the value of the quadratic.
f(x) = 2*(x + 7)^2 - 103
The graph is of the original quadratic.