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serious [3.7K]
3 years ago
14

Help on both of these pls also sry the lighting is weird

Mathematics
1 answer:
IRISSAK [1]3 years ago
5 0

Answer:

see explanation

Step-by-step explanation:

The 2 angles form a right angle, thus their sum is 90°, hence

4x + 7 + 35 = 90

4x + 42 = 90 ( subtract 42 from both sides )

4x = 48 ( divide both sides by 4 )

x = 12

-----------------------------------------------------

To calculate the slope m use the slope formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (0, 0) and (x₂, y₂ ) = (1, 4) ← 2 points on the line

m = \frac{4-0}{1-0} = \frac{4}{1} = 4


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Hiii please help i’ll give brainliest if you give a correct answer tysm!
sleet_krkn [62]

Answer:

d 380

Step-by-step explanation:

5 0
3 years ago
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Jaden learns to perform 2 vocal pieces during each week of lessons . How many weeks of lessons will Jaden need before he will be
storchak [24]

Answer:

12 weeks

Step-by-step explanation:

To solve this, all you need to do is divided 24 pieces by the two he learns per week. You'll then find it will take him 12 weeks

6 0
3 years ago
If $-2 < x \le 3,$ then find all possible values of $5x + 1.$ Give your answer in interval notation PLEASE ANSWER THUS PLEASE
exis [7]

Answer:

(-9,16]

Step-by-step explanation:

we know that

The domain of x is equal to the interval--------> (-2,3]

-2< x \leq 3

All real numbers greater than -2 and less than or equal to 3

Let

y=5x+1

For x=3

y=5x+1\\y=5(3)+1=16

For x>-2

y >5(-2)+1\\y > -9

so

The range of the function is the interval--------> (-9,16]

5 0
3 years ago
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Find the zeros of y = x2 – 6x – 4 by completing the square.
katrin [286]

Answer:

The solutions to the quadratic equations are:

x=\sqrt{13}+3,\:x=-\sqrt{13}+3

Step-by-step explanation:

Given the function

y\:=\:x^2\:-\:6x\:-\:4

substitute y = 0 in the equation to determine the zeros

0\:=\:x^2\:-\:6x\:-\:4

Switch sides

x^2-6x-4=0

Add 4 to both sides

x^2-6x-4+4=0+4

Simplify

x^2-6x=4

Rewrite in the form (x+a)² = b

But, in order to rewrite in the form x²+2ax+a²

Solve for 'a'

2ax = -6x

a = -3

so add a² = (-3)² to both sides

x^2-6x+\left(-3\right)^2=4+\left(-3\right)^2

x^2-6x+\left(-3\right)^2=13

Apply perfect square formula:  (a-b)² = a²-2ab+b²

\left(x-3\right)^2=13

\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}

solve

x-3=\sqrt{13}

Add 3 to both sides

x-3+3=\sqrt{13}+3

Simplify

x=\sqrt{13}+3

now solving

x-3=-\sqrt{13}

Add 3 to both sides

x-3+3=-\sqrt{13}+3

Simplify

x=-\sqrt{13}+3

Thus, the solutions to the quadratic equations are:

x=\sqrt{13}+3,\:x=-\sqrt{13}+3

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3 years ago
What is the unit rate and state rate of 253 for 20 hours?
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