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timofeeve [1]
3 years ago
10

Can someone help me ;-; With any questions, it doesnt have to be all of them-

Mathematics
2 answers:
Juli2301 [7.4K]3 years ago
8 0
14 = B. 11
15=. C.-2.
Sunny_sXe [5.5K]3 years ago
7 0
#14= B. 11
#15= C. -2
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Find the value of X and the value of Y. <br> (10 POINTS)
Ganezh [65]

sin 45 = opp/hyp

sin 45 = 4 / y

y = 4/sin 45

y = 4 /((sqrt2)/2)=4* sqrt(2)


tan 45 =opp/adj

tan 45 = 4/(x-3)

1 = 4/(x-3)

x-3 = 4

x=7


B

3 0
3 years ago
What is the length of BC? Round to the nearest tenth.
emmasim [6.3K]

9514 1404 393

Answer:

  (c) 14.5 cm

Step-by-step explanation:

The relevant trig relation is ...

  Sin = Opposite/Hypotenuse

  sin(65°) = BC/BA

  BC = BA·sin(65°) ≈ (16 cm)·0.9063 ≈ 14.501 cm

  BC ≈ 14.5 cm

_____

<em>Additional comment</em>

As is often the case, a simple estimate is all that is needed to identify the correct answer choice.

You only need to know how the long side of a right triangle compares to the others. In an isosceles right triangle, both legs are √2/2 ≈ 0.71 times the hypotenuse. The long side of a right triangle will never be shorter than that. This means the long side must be greater than about 11.2, and cannot be greater than 16. There is only one answer choice in that range.

4 0
3 years ago
Angle ABC is a straight angle. m∠DBC = 130° and BE bisects ∠ABD.<br><br><br> What is mEBA?
seraphim [82]
The answer:

we observe that <span>m∠DBC = 130° 
</span><span>
we should find the value of </span>mEDB to answer this question
Angle ABC is a straight angle, so m ABC= 180°, but 
mABD  + <span>m∠DBC = 180° (look at the figure)
</span>
so mABD= 180° - m∠DBC = 180 - 130 = 50°

therefore, mABD= 50°,
and BE bisects ∠ABD imiplies  mEBA = mEDB, and mABD=  mEBA + mEDB= 50°, it does mean 2x mEBA = 50°

and from where mEBA = 50°/2=25°
5 0
3 years ago
Read 2 more answers
50 points!!! will mark brainliest for correct answer!!
GenaCL600 [577]
A- Number of Sunlight (per year)
3 0
3 years ago
Read 2 more answers
For the composite function, identify an inside function and an outside function and write the derivative with respect to x of th
alexira [117]

Answer:

The inner function is h(x)=4x^2 + 8 and the outer function is g(x)=3x^5.

The derivative of the function is \frac{d}{dx}\left(3\left(4x^2+8\right)^5\right)=120x\left(4x^2+8\right)^4.

Step-by-step explanation:

A composite function can be written as g(h(x)), where h and g are basic functions.

For the function f(x)=3(4x^2+8)^5.

The inner function is the part we evaluate first. Frequently, we can identify the correct expression because it will appear within a grouping symbol one or more times in our composed function.

Here, we have 4x^2+8 inside parentheses. So h(x)=4x^2 + 8 is the inner function and the outer function is g(x)=3x^5.

The chain rule says:

\frac{d}{dx}[f(g(x))]=f'(g(x))g'(x)

It tells us how to differentiate composite functions.

The function f(x)=3(4x^2+8)^5 is the composition, g(h(x)), of

     outside function: g(x)=3x^5

     inside function: h(x)=4x^2 + 8

The derivative of this is computed as

\frac{d}{dx}\left(3\left(4x^2+8\right)^5\right)=3\frac{d}{dx}\left(\left(4x^2+8\right)^5\right)\\\\\mathrm{Apply\:the\:chain\:rule}:\quad \frac{df\left(u\right)}{dx}=\frac{df}{du}\cdot \frac{du}{dx}\\f=u^5,\:\:u=\left(4x^2+8\right)\\\\3\frac{d}{du}\left(u^5\right)\frac{d}{dx}\left(4x^2+8\right)\\\\3\cdot \:5\left(4x^2+8\right)^4\cdot \:8x\\\\120x\left(4x^2+8\right)^4

The derivative of the function is \frac{d}{dx}\left(3\left(4x^2+8\right)^5\right)=120x\left(4x^2+8\right)^4.

3 0
4 years ago
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