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3 years ago

The average gas mileage m in miles per gallon for a compact car is modeled by

Mathematics

1 answer:

Sauron [17]3 years ago

3 0

Answer:

In these functions translation is used.

The transformation means that vertex of function m(s) is translated 18 units downwards.

Step-by-step explanation:

We have been given that average gas mileage m in miles per gallon for a compact car is modeled by m(s) = - 0.015(s - 47)2 +33 and mileage for an SUV is modeled by my(s) = -0.015(s - 47)2 + 15.

We can see that both functions are parabolic and opens downwards. The vertex of function m(s) is (47,33), while vertex of function my(s) is (47,15). We can describe this change by translation.

This transformation means that function m(s) is translated 18 units downwards and average mileage of SUV is 18 miles/hour lesser than compact car at equal speeds.

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A and B are supplementary angles. If A = (5x + 27)° and B = (5x – 7)º, then find the measure of angle A.

vazorg [7]

Answer:

x=16

(5x + 27)° =5(16)+27=80+27=107

(5x – 7)º= 5(16)-7=80-7=73

Step-by-step explanation

supplementary angle=180

(5x + 27)° + (5x – 7)º=180

5x+27+5x-7=180

10x+20=180

10x=180-20

10x=160

x=160/10

x=16

(5x + 27)° =5(16)+27=80+27=107

(5x – 7)º= 5(16)-7=80-7=73

107+73=180

3 0

3 years ago

Spiral Review At a restaurant, Brianna and Naomi each order an appetizer for $6.50 and an entree for $9.75. They decide to leave

Licemer1 [7]

Answer: 4.55

Step-by-step explanation:

6.50x2 = 13 + 9.75 = 20% = 4.55

hoped this helped lol

4 0

3 years ago

The area of the triangle formed by x− and y− intercepts of the parabola y=0.5(x−3)(x+k) is equal to 1.5 square units. Find all p

Juliette [100K]

Check the picture below.

based on the equation, if we set y = 0, we'd end up with 0 = 0.5(x-3)(x-k).

and that will give us two x-intercepts, at x = 3 and x = k.

since the triangle is made by the x-intercepts and y-intercepts, then the parabola most likely has another x-intercept on the negative side of the x-axis, as you see in the picture, so chances are "k" is a negative value.

now, notice the picture, those intercepts make a triangle with a base = 3 + k, and height = y, where "y" is on the negative side.

let's find the y-intercept by setting x = 0 now,

$\bf y=0.5(x-3)(x+k)\implies y=\cfrac{1}{2}(x-3)(x+k)\implies \stackrel{\textit{setting x = 0}}{y=\cfrac{1}{2}(0-3)(0+k)} \\\\\\ y=\cfrac{1}{2}(-3)(k)\implies \boxed{y=-\cfrac{3k}{2}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{area of a triangle}}{A=\cfrac{1}{2}bh}~~ \begin{cases} b=3+k\\ h=y\\ \quad -\frac{3k}{2}\\ A=1.5\\ \qquad \frac{3}{2} \end{cases}\implies \cfrac{3}{2}=\cfrac{1}{2}(3+k)\left(-\cfrac{3k}{2} \right)$

$\bf \cfrac{3}{2}=\cfrac{3+k}{2}\left( -\cfrac{3k}{2} \right)\implies \stackrel{\textit{multiplying by }\stackrel{LCD}{2}}{3=\cfrac{(3+k)(-3k)}{2}}\implies 6=-9k-3k^2 \\\\\\ 6=-3(3k+k^2)\implies \cfrac{6}{-3}=3k+k^2\implies -2=3k+k^2 \\\\\\ 0=k^2+3k+2\implies 0=(k+2)(k+1)\implies k= \begin{cases} -2\\ -1 \end{cases}$

now, we can plug those values on A = (1/2)bh,

$\bf \stackrel{\textit{using k = -2}}{A=\cfrac{1}{2}(3+k)\left(-\cfrac{3k}{2} \right)}\implies A=\cfrac{1}{2}(3-2)\left(-\cfrac{3(-2)}{2} \right)\implies A=\cfrac{1}{2}(1)(3) \\\\\\ A=\cfrac{3}{2}\implies A=1.5 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{\textit{using k = -1}}{A=\cfrac{1}{2}(3+k)\left(-\cfrac{3k}{2} \right)}\implies A=\cfrac{1}{2}(3-1)\left(-\cfrac{3(-1)}{2} \right) \\\\\\ A=\cfrac{1}{2}(2)\left( \cfrac{3}{2} \right)\implies A=\cfrac{3}{2}\implies A=1.5$