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Alex787 [66]
3 years ago
6

Is line 1 (1,5) (3,-2) and like 2 (-3,2) (4,0) perpendicular of parallel?

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
7 0
  • Slope Formula: \frac{y_2-y_1}{x_2-x_1}

So remember that <u>perpendicular lines have slopes that are negative reciprocals to each other</u> and <u>parallel lines have the same slope.</u> To find out if they are either parallel or perpendicular, plug the pair of points into the slope formula to find their slopes:

\textsf{Line 1}\\\\\frac{5-(-2)}{1-3}=-\frac{7}{2}\\\\\textsf{Line 2}\\\\\frac{0-2}{4-(-3)}=-\frac{2}{7}

Since these slopes aren't the same nor are they negative reciprocals to each other, <u>the lines are neither parallel nor perpendicular.</u>

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Answer:

(x-7)^2+(y-1)^2+(z+1)^2-9\le 0

Step-by-step explanation:

A ball is the solid inside a surface which is a sphere.

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(x-h)^2+(y-k)^2+(z-s)^2= r^2

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When we plug the given center (7,1,-1) and radius 3 we get:

(x-7)^2+(y-1)^2+(z+1)^2= 3^2

Then we turn this into an inequality: Since the ball is inside the surface we must use the \le symbol.

(x-7)^2+(y-1)^2+(z+1)^2\le 9

Then we just subtract 9 from both sides to get:

(x-7)^2+(y-1)^2+(z+1)^2-9\le 0

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3 years ago
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Answer:

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Since "Sine" is Opposite/Hypotenuse and Cosine is adjacent hypotenuse...

The opposite of angle A is 12, and the hypotenuse is 12, therefore making 12/13.

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