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gogolik [260]
3 years ago
5

Diagnose this case study.A 68 year old patient with Alzheimer disease was brought to the emergency room by the staff of a local

nursing home. He presented as lethargic with a sallow complexion. He had an admission temperature of 102.4F and a respiratory rate of 33/minute. During respiration, the right side of his chest moved better than the left. He showed dense consolidation of the lower lobe of the left lung on physical exam. A sputum sample revealed blood and a greenish color. A chest x-ray showed tight consolidation of the left lung with evidence of formation of cavities in the lung tissue from cytotoxic damage. The patient complained of chills in the exam room, combined with his fever. A smear of his sputum demonstrated no acid- fast bacteria.
Biology
1 answer:
goldfiish [28.3K]3 years ago
6 0

The question is incomplete. The information asked in the question is as follows:

What is your presumptive diagnosis for this case?

Caused by which organism?

What evidence could the sputum give for this case?

Is the increased respiration rate and unequal chest movement indicative of the pathology?

Is this a bacterial or viral disease?

Answer:

Alzheimer disease may be defined as a type of the progressive disorder that mainly destroys the memorizing capacity of the individual. The disease gets worsen with the age.

After studying the case disease given in the question it can be inferred that the individual might have pneumonia caused by the bacteria  Klebsiella. This causes the damage to the lungs. The sputum shows that the bacteria is gram negative that are covered with the rods. If the bacteria is grown on the agar plate of the MacConkey, the bacteria becomes mucoid due to the production of the slime. This might cause the lung damage and causes inflammation that causes the observable changes. This is a bacterial disease.

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Answer:

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According to the information obtained we deduce:

Comb shape is produced by R and P

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Rr pp × rr Pp will produce from the interbreeding: 2 walnuts, 1 single and 1 pea offspring.

We deduce that for the pink comb the genotype is: Rrpp

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Rr pp × rr Pp generates crosslinks containing RrPp, rrPp, rrpp as children in a 2: 1: 1 ratio.

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