Dakota knows that EJ←→⊥CN←→ and CN←→∥KT←→ .
1 answer:
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Check the picture:
Rotating JKL 180° with respect to the origin, and translating it 1 unit up, we get J'K'L'.
That is, the 2 triangles match perfectly.
Answer:
<span>△JKL is congruent to △J′K′L′ because you can map △JKL to △J′K′L′ using a rotation of 180° about the origin followed by a translation 1 unit up, which is a sequence of rigid motions.</span>
Rotating JKL 180° with respect to the origin, and translating it 1 unit up, we get J'K'L'.
That is, the 2 triangles match perfectly.
Answer:
<span>△JKL is congruent to △J′K′L′ because you can map △JKL to △J′K′L′ using a rotation of 180° about the origin followed by a translation 1 unit up, which is a sequence of rigid motions.</span>