All categories

3 years ago

Dakota knows that EJ←→⊥CN←→ and CN←→∥KT←→ .

Mathematics

1 answer:

Lina20 [59]3 years ago

6 0

Answer:

m∠CJV=90°
EV←→⊥KT←→

Step-by-step explanation:

Nothing in the problem statement tells you anything about the directions of lines LK or QT, so you cannot conclude they are parallel. You only know that EV crosses CN and KT at right angles.

EJ ⊥ CN means m∠CJV = 90°, as all angles at the intersection of EJ and CN are 90°.

You might be interested in

Help me please Find the measure of angle QST

Oksi-84 [34.3K]

Answer:

Angle QST=52°+47°

=99°

3 0

2 years ago

A bottle holds 24 ounces of water. It has x ounces of water in it. What does 24 - x represent in the situation?

Misha Larkins [42]

It represents the ounces of water that the bottle can still hold.

4 0

3 years ago

Read 2 more answers

Suppose $p(x)$ is a monic cubic polynomial with real coefficients such that $p(3-2i)=0$ and $p(0)=-52$. determine $p(x)$ (in exp

Maslowich

If $p(3-2i)=0,$ then complex number $3-2i$ is a root of cubic polynomial.

If polynomial has real coefficients, then conjugated $3+2i$ is also a root of polynomial.

Then the polynomial will be of a form

$p(x)=(x-(3-2i))(x-(3+2i))(x-a).$

Since $p(0)=-52,$ then

$-52=(0-(3-2i))(0-(3+2i))(0-a),\\ \\-52=(2i-3)(3+2i)a,\\ \\-52=(4i^2-9)a,\\ \\-52=(-4-9)a,\\ \\-13a=-52,\\ \\a=4.$

Therefore,

$p(x)=(x-(3-2i))(x-(3+2i))(x-4),\\ \\p(x)=(x^2-6x+13)(x-4),\\ \\p(x)=x^3-10x^2+37x-52.$

3 0

2 years ago

Solve the equation 15x=60

Tcecarenko [31]

Answer:

x = 4

Step-by-step explanation:

3 0

3 years ago

Can lengths 7,1,7 form a triangle

Vadim26 [7]

Answer:

Yes

Step-by-step explanation:

There is no unclosable gap. 7+1>7. 7+7>1. An isosceles triangle would be formed.

4 0

2 years ago