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2 years ago

What is the repricol of 7 1/3 ? ( please im on a test)

Mathematics

1 answer:

Radda [10]2 years ago

5 0

Answer:

3/22

Step-by-step explanation:

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A jar contains 133. A bigger jar contains 1 2/7 times as many pennies.what is the value of the pennies in the bigger jar

adoni [48]

A jar contains 133 pennies....a bigger jar contains 1 2/7 times as much

so the bigger jar contains :
1 2/7 * 133
9/7 * 133 =
1197/7 =
171 pennies <===

4 0

3 years ago

Please answer asap!!!!

galina1969 [7]

Answer:

B. 126 degrees

Step-by-step explanation:

lets say the angle is x

the equation we have here is the 8th graders divided by the total number of students is equal to x divided by 360 degrees since a circle has a 360 degree angle.

The equation is:

350/1000=x/360

in number form.

350/1000= 0.35 = 35%

so now we know x/360=35%

126/360=35%

so the answer would be 126 degrees.

Hope that was helpful, if it was please rate it for anyone else who is asking the same question.

4 0

3 years ago

Simplify (2x²-6x-8)÷(x-4)

Norma-Jean [14]

Answer: Heyaa!

The Answer is 2x+2

Step-by-step explanation:

Simplify the expression.

hopefully this helps you !

- Matthew ~

3 0

2 years ago

Read 2 more answers

(2 - 5m) (-5) dhwfhsdjduhrhdb ewdewg

Semmy [17]

Answer:

25m−10 would be the answer

5 0

3 years ago

In right △ABC, the altitude CH to the hypotenuse AB intersects angle bisector AL in point D. Find the sides of △ABC if AD = 8 cm

tangare [24]

Answer:

$AC=8\sqrt{3}\ cm\\ \\AB=16\sqrt{3}\ cm\\ \\BC=24\ cm$

Step-by-step explanation:

Consider right triangle ADH ( it is right triangle, because CH is the altitude). In this triangle, the hypotenuse AD = 8 cm and the leg DH = 4 cm. If the leg is half of the hypotenuse, then the opposite to this leg angle is equal to 30°.

By the Pythagorean theorem,

$AD^2=AH^2+DH^2\\ \\8^2=AH^2+4^2\\ \\AH^2=64-16=48\\ \\AH=\sqrt{48}=4\sqrt{3}\ cm$

AL is angle A bisector, then angle A is 60°. Use the angle's bisector property:

$\dfrac{CA}{CD}=\dfrac{AH}{HD}\\ \\\dfrac{CA}{CD}=\dfrac{4\sqrt{3}}{4}=\sqrt{3}\Rightarrow CA=\sqrt{3}CD$

Consider right triangle CAH.By the Pythagorean theorem,

$CA^2=CH^2+AH^2\\ \\(\sqrt{3}CD)^2=(CD+4)^2+(4\sqrt{3})^2\\ \\3CD^2=CD^2+8CD+16+48\\ \\2CD^2-8CD-64=0\\ \\CD^2-4CD-32=0\\ \\D=(-4)^2-4\cdot 1\cdot (-32)=16+128=144\\ \\CD_{1,2}=\dfrac{-(-4)\pm\sqrt{144}}{2\cdot 1}=\dfrac{4\pm 12}{2}=-4,\ 8$

The length cannot be negative, so CD=8 cm and

$CA=\sqrt{3}CD=8\sqrt{3}\ cm$

In right triangle ABC, angle B = 90° - 60° = 30°, leg AC is opposite to 30°, and the hypotenuse AB is twice the leg AC. Hence,

$AB=2CA=16\sqrt{3}\ cm$

By the Pythagorean theorem,

$BC^2=AB^2-AC^2\\ \\BC^2=(16\sqrt{3})^2-(8\sqrt{3})^2=256\cdot 3-64\cdot 3=576\\ \\BC=24\ cm$

3 0

3 years ago