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slamgirl [31]
3 years ago
6

If x and y are integers greater than 1, is x a multiple of y ? (1) \small 3y^{2}+7y=x (2) \small x^{2}-x is a multiple of y. Sta

tement (1) ALONE is sufficient, but statement (2) alone is not sufficient. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient. EACH statement ALONE is sufficient. Statements (1) and (2) TOGETHER are NOT sufficient.
Mathematics
1 answer:
Nata [24]3 years ago
8 0

Answer:

Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

Step-by-step explanation:

A multiple of a number is obtained after multiplying the number by an integer.

Here,

x, y are any two integers greater than 1,

(1) We have,

\small 3y^{2}+7y=x

\implies y(3y+7) = x

∵ y is an integer ⇒ 3y + 7 is also an integer,

⇒ y × an integer = x

That is, when we multiply y by a number we obtain x,

∴ x is a multiple of y.

Thus, statement (1) ALONE is sufficient.

(2),

\small x^{2}-x\text{ is a multiple of y}

I.e.

y\times a = x^2-x, where a is an integer,

\implies y\times a = x(x-1)

∵ x and x - 1 are disjoint numbers,

There are three possible cases,

Case 1 : x is multiple of y

Case 2 : (x-1) is a multiple of y,

Case 3 : neither x nor x - 1 are multiple of y but their product is multiple of y,

Thus, statement (2) is not sufficient.

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Tanya spent 1/5 of her allowance on candy and 2/3 on food. What fraction of her allowance did Tanya spend on food and candy alto
kari74 [83]
13/15 of her allowance was spent in total.

To solve this, you'd need to find the least common denominator (LCD) so that both fractions have the same number on the bottom. In this case, the first number that you could get with 5 and 3 was 15.

Next, you'd have to multiply the numerator by the same amount as the denominator, so that the fractions are proportionate. So, for 1/5, since we had to multiply 5 by 3 to get 15, we'd multiply 1 by 3 as well, giving us 3/15. Doing the same with 2/3, we'd get 10/15.

Then, you add the two fractions together (10/15 + 3/15 = 13/15).

Now, in any other case, you could probably simplify the fraction after you've solved the problem. If we got 12/15 instead of 13/15, then we could simplify that to 4/5, since both 12 and 15 are divisible by 3. But in this case, this is the simplest form of that fraction.

Hope this helped!!!
8 0
3 years ago
1.36 in word form please help me
kicyunya [14]
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                                          OR
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7 0
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Miguel has 7 days to read a 96. Page book. He wants to find out how many pages he needs to read each day to finish the book in t
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Step-by-step explanation:

96/7

≈13.7

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6 0
2 years ago
Blood pressure values are often reported to the nearest 5 mmHg (100, 105, 110, etc.). The actual blood pressure values for nine
Paladinen [302]

Answer:

a) 117.4

b) 117.9

c) Option A)  When there is rounding or grouping, the median can be highly sensitive to small change

Step-by-step explanation:

We are given the following data set in the question:

108.6, 117.4, 128.4, 120.0, 103.7, 112.0, 98.3, 121.5, 123.2

Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}

n = 9

a) Median of the reported blood pressure values

Sorted Values: 98.3, 103.7, 108.6, 112.0, 117.4, 120.0, 121.5, 123.2, 128.4

Median =

\dfrac{9 + 1}{2}^{th}\text{ term} = 5^{th}\text{ term} = 117.4

b) New median of the reported values

Data: 108.6, 117.9, 128.4, 120.0, 103.7, 112.0, 98.3, 121.5, 123.2

Sorted Values: 98.3, 103.7, 108.6, 112.0, 117.9, 120.0, 121.5, 123.2, 128.4

New Median =

\dfrac{9 + 1}{2}^{th}\text{ term} = 5^{th}\text{ term} = 117.9

c) Since median is a position based descriptive statistics, a small change in values can bring a change in the median value as the order of the data may change.

Option A)  When there is rounding or grouping, the median can be highly sensitive to small change

7 0
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