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oee [108]
3 years ago
13

Please help, if you answer thanks :) will mark brainliest

Mathematics
1 answer:
nignag [31]3 years ago
5 0

I believe the correct answer is C.

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How do you solve this?
Hatshy [7]

Answer:

y = -3/2x + 5/2

Step-by-step explanation:

Point: (5, -5)

Parallel to: y = -3/2x + 2

Slope= -3/2 (parallel lines have the same slope)

y-intercept = -5 - (-3/2)(5) (y - slope times x) =

-5 + 15/2 = 5/2

8 0
2 years ago
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otez555 [7]
The answer is A(45) = -211
3 0
3 years ago
Graph the following inequality :<br> - 2y z x + 6
saul85 [17]

Answer: 2(-2x+3)

Step-by-step explanation:

6 0
3 years ago
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Need help so much on Circle<br><br> Please help me for my geometry honors work please! Thank you
vichka [17]

Answer:

x = 95

Step-by-step explanation:

The total degree of a circle is 360. The twp arcs on each side of the parallel lines are equal.

Subtract 135 and 35 from your total

<em>360 - 135 - 35 = 190</em>

Divide your answer by 2

<em>190 ÷ 2 = 95</em>

6 0
2 years ago
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To assess the precision of a laboratory scale, we measure a block known to have a mass of 1 gram. we measure the block n times a
vlada-n [284]
<span>n = 5 The formula for the confidence interval (CI) is CI = m ± z*d/sqrt(n) where CI = confidence interval m = mean z = z value in standard normal table for desired confidence n = number of samples Since we want a 95% confidence interval, we need to divide that in half to get 95/2 = 47.5 Looking up 0.475 in a standard normal table gives us a z value of 1.96 Since we want the margin of error to be ± 0.0001, we want the expression ± z*d/sqrt(n) to also be ± 0.0001. And to simplify things, we can omit the ± and use the formula 0.0001 = z*d/sqrt(n) Substitute the value z that we looked up, and get 0.0001 = 1.96*d/sqrt(n) Substitute the standard deviation that we were given and 0.0001 = 1.96*0.001/sqrt(n) 0.0001 = 0.00196/sqrt(n) Solve for n 0.0001*sqrt(n) = 0.00196 sqrt(n) = 19.6 n = 4.427188724 Since you can't have a fractional value for n, then n should be at least 5 for a 95% confidence interval that the measured mean is within 0.0001 grams of the correct mass.</span>
8 0
2 years ago
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