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kompoz [17]
4 years ago
5

Johnny earned a total of $15 for 3

Mathematics
1 answer:
solniwko [45]4 years ago
4 0

Answer:

5 dollars a hour. ,

Step-by-step explanation:

count by fives

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Answer A and D are equivalent to 4(42).
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Find the common ratio of the geometric sequence 6, 48, 384, ...​
gregori [183]

Answer:

r = 8

Step-by-step explanation:

The common ratio r of a geometric sequence is

r = \frac{a_{2} }{a_{1} } = \frac{a_{3} }{a_{2} } = ..... = \frac{a_{n} }{a_{n-1} }

Then

r = \frac{48}{6} = \frac{384}{48} = 8

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3 years ago
I seriously need help
777dan777 [17]

Answer:

x(t) = - 5 + 6t and y(t) = 3 - 9t

Step-by-step explanation:

We have to identify the set of parametric equations over the interval 0 ≤ t ≤ 1 defines the line segment with initial point (-5,3) and terminal point (1,-6).

Now, put t = 0 in the sets of parametric equations in the options so that the x value is - 5 and the y-value is 3.

x(t) = - 5 + t and y(t) = 3 - 6t and  

x(t) = - 5 + 6t and y(t) = 3 - 9t

Both of the above sets of equations satisfy this above conditions.

Now, put t = 1 in both the above sets of parametric equations and check where we get x = 1 and y = -6.

So, the only set, x(t) = - 5 + 6t and y(t) = 3 - 9t  satisfies this condition.

Therefore, this is the answer. (Answer)

8 0
3 years ago
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