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svet-max [94.6K]
3 years ago
7

Four less than the quotient of a number 1 and 5.

Mathematics
2 answers:
WINSTONCH [101]3 years ago
7 0

Answer:

1/5 - 4

Step-by-step explanation:

Quotient of a number 1 and 5 which is 1/5

four less which is -4

If you put these together, it becomes 1/5-4

zhannawk [14.2K]3 years ago
5 0

Answer:

Step-by-step explanation:

You should know that quotient is the result of division.

 

n/2

 

Four less than that would be subtracting.

 

(n/2) - 4 = 9

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Solve 73 make sure to also define the limits in the parts a and b
Aleks04 [339]

73.

f(x)=\frac{3x^4+3x^3-36x^2}{x^4-25x^2+144}

a)

\lim_{x\to\infty}f(x)=\lim_{x\to\infty}(\frac{3+\frac{3}{x}-\frac{36}{x^2}}{1-\frac{25}{x^2}+\frac{144}{x^4}})=3\lim_{x\to-\infty}f(x)=\lim_{x\to-\infty}(\frac{3+\frac{3}{x}-\frac{36}{x^2}}{1-\frac{25}{x^2}+\frac{144}{x^4}})=3\cdot\frac{1}{2}=3

b)

Since we can't divide by zero, we need to find when:

x^4-2x^2+144=0

But before, we can factor the numerator and the denominator:

\begin{gathered} \frac{3x^2(x^2+x-12)}{x^4-25x^2+144}=\frac{3x^2((x+4)(x-3))}{(x-3)(x-3)(x+4)(x+4)} \\ so: \\ \frac{3x^2}{(x+3)(x-4)} \end{gathered}

Now, we can conclude that the vertical asymptotes are located at:

\begin{gathered} (x+3)(x-4)=0 \\ so: \\ x=-3 \\ x=4 \end{gathered}

so, for x = -3:

\lim_{x\to-3^-}f(x)=\lim_{x\to-3^-}-\frac{162}{x^4-25x^2+144}=-162(-\infty)=\infty\lim_{x\to-3^+}f(x)=\lim_{x\to-3^+}-\frac{162}{x^4-25x^2+144}=-162(\infty)=-\infty

For x = 4:

\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty

4 0
10 months ago
Eileen drove for 85 minutes. This is 21 more minutes than one third the number of minutes Ethan drove. How do I put this into an
Lapatulllka [165]
So let's start out by labeling Ethan as X

Since 85 is 1/3 of what Ethan drove, that means Ethan drove 3 times of 85.

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6 0
2 years ago
Read 2 more answers
The length of a rectangle is "a" inches and the width is 3 inches more than its length. find the perimeter and the area
Alex73 [517]

Answer:

Step-by-step explanation:

Givens

Length = a

Width = a + 3

Formulas

P = 2L + 2w

Area = L * w

Solution

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P = 2*a + 2(a + 3)             Remove the Brackets

p = 2a + 2a + 6                Combine

<u><em>P = 4a + 6</em></u>

Area

Area = L * w

Area = a (a + 3)

<u><em>Area = a^2 + 3a</em></u>

7 0
2 years ago
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