Answer:
206480
Step-by-step explanation:
Don't even bother with this part ever.
379x=89
_______
379 =379
x=0.21
Answer: ![16.56\ ft](https://tex.z-dn.net/?f=16.56%5C%20ft)
Step-by-step explanation:
You must draw a right triangle as the one attached, where "x" is the lenght in feet of the ramp.
You need to use the following Trigonometric Identity:
![sin\alpha=\frac{opposite}{hypotenuse}](https://tex.z-dn.net/?f=sin%5Calpha%3D%5Cfrac%7Bopposite%7D%7Bhypotenuse%7D)
In this case you can identify that:
![\alpha =25\°\\\\opposite=7\\\\hypotenuse=x](https://tex.z-dn.net/?f=%5Calpha%20%3D25%5C%C2%B0%5C%5C%5C%5Copposite%3D7%5C%5C%5C%5Chypotenuse%3Dx)
Now you must substitute these values into
:
![sin(25\°)=\frac{7}{x}](https://tex.z-dn.net/?f=sin%2825%5C%C2%B0%29%3D%5Cfrac%7B7%7D%7Bx%7D)
Finally, you must solve for "x" in order to find its value.
This is:
![sin(25\°)=\frac{7}{x}\\\\xsin(25\°)=7\\\\x=\frac{7}{sin(25\°)}\\\\x=16.56](https://tex.z-dn.net/?f=sin%2825%5C%C2%B0%29%3D%5Cfrac%7B7%7D%7Bx%7D%5C%5C%5C%5Cxsin%2825%5C%C2%B0%29%3D7%5C%5C%5C%5Cx%3D%5Cfrac%7B7%7D%7Bsin%2825%5C%C2%B0%29%7D%5C%5C%5C%5Cx%3D16.56)
Answer:
As angle B is a right triangle, the sides AB and CB are perpendicular to each other. From the property of all tangents to a circle given in the beginning it can be concluded that AB is a tangent of the circle
Answer:
![P(X\leq 1) = 0.331](https://tex.z-dn.net/?f=P%28X%5Cleq%201%29%20%3D%200.331)
Step-by-step explanation:
Given
Poisson Distribution;
Average rent in a week = 2.3
Required
Determine the probability of renting no more than 1 apartment
A Poisson distribution is given as;
![P(X = x) = \frac{y^xe^{-y}}{x!}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20%5Cfrac%7By%5Exe%5E%7B-y%7D%7D%7Bx%21%7D)
Where y represents λ (average)
y = 2.3
<em>Probability of renting no more than 1 apartment = Probability of renting no apartment + Probability of renting 1 apartment</em>
<em />
Using probability notations;
![P(X\leq 1) = P(X=0) + P(X =1)](https://tex.z-dn.net/?f=P%28X%5Cleq%201%29%20%3D%20P%28X%3D0%29%20%2B%20P%28X%20%3D1%29)
Solving for P(X = 0) [substitute 0 for x and 2.3 for y]
![P(X = 0) = \frac{2.3^0 * e^{-2.3}}{0!}](https://tex.z-dn.net/?f=P%28X%20%3D%200%29%20%3D%20%5Cfrac%7B2.3%5E0%20%2A%20e%5E%7B-2.3%7D%7D%7B0%21%7D)
![P(X = 0) = \frac{1 * e^{-2.3}}{1}](https://tex.z-dn.net/?f=P%28X%20%3D%200%29%20%3D%20%5Cfrac%7B1%20%2A%20e%5E%7B-2.3%7D%7D%7B1%7D)
![P(X = 0) = e^{-2.3}](https://tex.z-dn.net/?f=P%28X%20%3D%200%29%20%3D%20e%5E%7B-2.3%7D)
![P(X = 0) = 0.10025884372](https://tex.z-dn.net/?f=P%28X%20%3D%200%29%20%3D%200.10025884372)
Solving for P(X = 1) [substitute 1 for x and 2.3 for y]
![P(X = 1) = \frac{2.3^1 * e^{-2.3}}{1!}](https://tex.z-dn.net/?f=P%28X%20%3D%201%29%20%3D%20%5Cfrac%7B2.3%5E1%20%2A%20e%5E%7B-2.3%7D%7D%7B1%21%7D)
![P(X = 1) = \frac{2.3 * e^{-2.3}}{1}](https://tex.z-dn.net/?f=P%28X%20%3D%201%29%20%3D%20%5Cfrac%7B2.3%20%2A%20e%5E%7B-2.3%7D%7D%7B1%7D)
![P(X = 1) =2.3 * e^{-2.3}](https://tex.z-dn.net/?f=P%28X%20%3D%201%29%20%3D2.3%20%2A%20e%5E%7B-2.3%7D)
![P(X = 1) = 2.3 * 0.10025884372](https://tex.z-dn.net/?f=P%28X%20%3D%201%29%20%3D%202.3%20%2A%200.10025884372)
![P(X = 1) = 0.23059534055](https://tex.z-dn.net/?f=P%28X%20%3D%201%29%20%3D%200.23059534055)
![P(X\leq 1) = P(X=0) + P(X =1)](https://tex.z-dn.net/?f=P%28X%5Cleq%201%29%20%3D%20P%28X%3D0%29%20%2B%20P%28X%20%3D1%29)
![P(X\leq 1) = 0.10025884372 + 0.23059534055](https://tex.z-dn.net/?f=P%28X%5Cleq%201%29%20%3D%200.10025884372%20%2B%200.23059534055)
![P(X\leq 1) = 0.33085418427](https://tex.z-dn.net/?f=P%28X%5Cleq%201%29%20%3D%200.33085418427)
![P(X\leq 1) = 0.331](https://tex.z-dn.net/?f=P%28X%5Cleq%201%29%20%3D%200.331)
Hence, the required probability is 0.331