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Answer:
The solution code is written in Java
- public static void checkCommonValues(int arr1[], int arr2[]){
- if(arr1.length < arr2.length){
- for(int i = 0; i < arr1.length; i++){
- for(int j = 0; j < arr2.length; j++){
- if(arr1[i] == arr2[j]){
- System.out.print(arr1[i] + " ");
- }
- }
- }
- }
- else{
- for(int i = 0; i < arr2.length; i++){
- for(int j = 0; j < arr1.length; j++){
- if(arr2[i] == arr1[j]){
- System.out.print(arr2[i] + " ");
- }
- }
- }
- }
- }
Explanation:
The key idea of this method is to repeated get a value from the shorter array to check against the all the values from a longer array. If any comparison result in True, the program shall display the integer.
Based on this idea, an if-else condition is defined (Line 2). Outer loop will traverse through the shorter array (Line 3, 12) and the inner loop will traverse the longer array (Line 4, 13). Within the inner loop, there is another if condition to check if the current value is equal to any value in the longer array, if so, print the common value (Line 5-7, 14-16).
Answer:
a.
++score = score + 1
Explanation:
First you have to understand the increment operator;
There are three possible ways to increment the value of variable by 1.
1. <u>post increment</u>
syntax:
name++
it using in expression first then increase the value by 1.
2. <u>Pre increment</u><u> </u>
syntax:
++name
it increase the value by 1 before it using in expression.
3. simple method
name = name +1
In the question,
option 1: ++score = score + 1
it increase the value of score by 2 because their are two increment is used first for (score + 1) and second ++score.
Therefore, the correct option is a.
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