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vichka [17]
4 years ago
10

Plz help I need this tonite because I tern it in tomorrow

Mathematics
2 answers:
ankoles [38]4 years ago
6 0

Plugging it in, you get 6*125+40. 6*125 is equal to 750. So 750 +40=790.


erma4kov [3.2K]4 years ago
5 0

Answer:

Is it write?????????????????????????????

Step-by-step explanation:


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Step-by-step explanation:

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Find two numbers the quotient is between. 175/6
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Sidana [21]

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8 0
3 years ago
A certain transverse wave is described by y(x,t)=bcos[2π(xl−tτ)], where b = 5.90 mm , l = 29.0 cm , and τ = 3.90×10−2 s .
Vitek1552 [10]
Part A:

The general form of the equation of a transverse wave is given by:

y(x,t)=A\cos\left[2\pi\left( \frac{x}{\lambda} - \frac{t}{T} \right)\right]

where A is the amplitude, \lambda is the wavelength, and T is the period.

Given that a certain transverse wave is described by:

y(x,t)=bcos[2\pi(xl-t\tau)], where b = 5.90 mm , l = 29.0 cm , and \tau = 3.90\times10^{-2} s

Thus, the amplitude is b = 5.90 mm = 5.9\times10^{-3} \ m



Part B:

The general form of the equation of a transverse wave is given by:

y(x,t)=A\cos\left[2\pi\left( \frac{x}{\lambda} - \frac{t}{T} \right)\right]

where A is the amplitude, \lambda is the wavelength, and T is the period.

Given that a certain transverse wave is described by:

y(x,t)=bcos[2\pi\left(\frac{x}{l}-\frac{t}{tau}\right)\right], where b = 5.90 mm , l = 29.0 cm , and \tau = 3.90\times10^{-2} s

<span>Thus,

y(x,t)=bcos[2\pi\left(\frac{x}{l}-\frac{t}{tau}\right)\right\\ \\ \frac{1}{\lambda} = \frac{1}{l}  \\  \\  \Rightarrow\lambda= l =28.0 \ cm=\bold{2.8\times10^{-1}}



Part C:

</span><span>The general form of the equation of a transverse wave is given by:

y(x,t)=A\cos\left[2\pi\left( \frac{x}{\lambda} - \frac{t}{T} \right)\right]

where A is the amplitude, \lambda is the wavelength, and T is the period.

</span><span>Given that a certain transverse wave is described by:

y(x,t)=bcos[2\pi\left(\frac{x}{l}-\frac{t}{tau}\right)\right], where b = 5.90 mm , l = 29.0 cm , and \tau = 3.90\times10^{-2} s
</span>
<span>The wave's frequency, f, is given by:

</span>f= \frac{1}{T} = \frac{1}{\tau} = \frac{1}{3.40\times10^{-2}} =\bold{29.4 \ Hz}



Part D:

Given that the <span>the wavelength is 2.8\times10^{-1} \ m </span><span>and that the wave's frequency is 29.4 Hz

</span><span>The wave's speed of propagation, v, is given by:
</span>
v=f\lambda=29.4(2.8\times10^{-1})=8.232 \ m/s
4 0
3 years ago
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