First of all to transfer <span>(2x - 1)(x + 6) = 0 into a form where we can plug it into the quadratic formula we need to use the FOIL method.
</span><span>(2x - 1)(x + 6) = 0
</span> becomes
2x*x+2x*6+-1*x+-1*6
which simplifies to
2x^2 + 12x - x - 6
and then we add like terms to get
2x^2 + 11x - <span>6
</span>
now that it is in the correct form we can identify "a" "b" and "c" by following this form
ax^2 + bx + c
looking back at the equation we got earlier
2x^2 + 11x - <span>6</span>
a=2,b=11,and c=-6
He has 19 because it wore a different cap for each hour and cups to his rip
F(x)=34x-84 ............................
The first one is. the second is 'prime'
