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Nat2105 [25]
3 years ago
10

Just number 14 please

Mathematics
1 answer:
larisa [96]3 years ago
4 0
Nope you posted this five days ago no need for another answer.
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What is 2,871,000,000 in scientific notation
Nimfa-mama [501]

Answer:

2.871*10^9

Step-by-step explanation:

add a decimal point at the end of the number ( 2,871,000,000.) then count how many places it takes to move the decimal point between the first and second number (2.8) then write the rest of the numbers higher than "0" after, giving you the 2.871

to show that the number written is in scientific notation you add 10 to the power of the amount of times you moved the decimal place. In this case, because the decimal point was moved a total of 9 times, it would be 10 to the 9th power (10^9).

3 0
2 years ago
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Tony rounded each of the numbers 1183 and 1145 to the nearest hundred. Which choice correctly compares the rounded numbers
Mamont248 [21]
1183 rounded to the nearest hundred = 1200
1145 rounded to the nearest hundred = 1100
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2 years ago
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Every month Jordan puts $14 into her bank account. Her grandma puts additional money into Jordan's bank account every month. Aft
vesna_86 [32]

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D $48.00 u need to multiply 216 and 12 to get 48

8 0
2 years ago
The width-to-height ratio of a certain computer monitor
Mnenie [13.5K]
<h2>24 inches</h2>

Step-by-step explanation:

It is given that \frac{\textbf{width of computer monitor}}{\textbf{height of computer monitor}}=\frac{16}{9}

It is given that \text{height of computer monitor}=13.5

\text{width of computer monitor} =\text{height of computer monitor}\times \frac{16}{9}

\text{width of computer monitor}=13.5\times \frac{16}{9} =\frac{216}{9} =24

Hence the required width in inches is 24.

5 0
3 years ago
Prove that (Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A
iVinArrow [24]

Answer:

The answer is below

Step-by-step explanation:

We need to prove that:

(Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A.

Firstly, 1 / cos A = sec A, 1 / sin A = cosec A and tanA = sinA / cosA.

Also, 1 + tan²A = sec²A; sec²A - 1 = tan²A

\frac{\sqrt{secA-1} }{\sqrt{secA+1} } +\frac{\sqrt{secA+1} }{\sqrt{secA-1} } =\frac{(\sqrt{secA-1)}(\sqrt{secA-1})+(\sqrt{secA+1)}(\sqrt{secA+1}) }{(\sqrt{secA+1})(\sqrt{secA-1}) } \\\\=\frac{secA-1+(secA+1)}{\sqrt{sec^2A-secA+secA-1} } \\\\=\frac{2secA}{\sqrt{sec^2A-1} } \\\\=\frac{2secA}{\sqrt{tan^2A} } \\\\=\frac{2secA}{tanA} \\\\=\frac{2*\frac{1}{cosA} }{\frac{sinA}{cosA} }\\\\= 2*\frac{1}{cosA}*\frac{cosA}{sinA}\\\\=2*\frac{1}{sinAA}\\\\=2cosecA

7 0
3 years ago
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