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lesantik [10]
3 years ago
9

Show that 2 - sqrt(2) is irrational

Mathematics
1 answer:
babunello [35]3 years ago
3 0

Answer:

This proof can be done by contradiction.

Let us assume that 2 - √2 is rational number.

So, by the definition of rational number, we can write it as

2 -\sqrt{2} = \dfrac{a}{b}

where a & b are any integer.

⇒ \sqrt{2} = 2 - \dfrac{a}{b}

Since, a and b are integers 2 - \dfrac{a}{b} is also rational.

and therefore √2 is rational number.

This contradicts the fact that √2 is irrational number.

Hence our assumption that 2 - √2 is rational number is false.

Therefore, 2 - √2 is irrational number.

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