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Firlakuza [10]
3 years ago
5

In the figure below, if BE is the perpendicular bisector of AD, what is the value of x?

Mathematics
1 answer:
dedylja [7]3 years ago
4 0

Both sides would be the same, so set them to equal ans solve for x.


3x+4 = 2x +7

Subtract 4 from each side:

3x = 2x +3

Subtract 2x from each side:

x = 3

The answer is X =  3.

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the length of the table is 108 inches

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Solve each system of linear equations by elimination. <br><br>2v=-5 +10 <br>-15=-3x + 5y​
Burka [1]

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Step-by-step explanation:

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2 years ago
Let U1, ..., Un be i.i.d. Unif(0, 1), and X = max(U1, ..., Un). What is the PDF of X? What is EX? Hint: Find the CDF of X first,
Kryger [21]

Answer:

E(X)= n \int_{0}^1 x^n dx = n [\frac{1}{n+1}- \frac{0}{n+1}]=\frac{n}{n+1}

Step-by-step explanation:

A uniform distribution, "sometimes also known as a rectangular distribution, is a distribution that has constant probability".

We need to take in count that our random variable just take values between 0 and 1 since is uniform distribution (0,1). The maximum of the finite set of elements in (0,1) needs to be present in (0,1).

If we select a value x \in (0,1) we want this:

max(U_1, ....,U_n) \leq x

And we can express this like that:

u_i \leq x for each possible i

We assume that the random variable u_i are independent and P)U_i \leq x) =x from the definition of an uniform random variable between 0 and 1. So we can find the cumulative distribution like this:

P(X \leq x) = P(U_1 \leq 1, ...., U_n \leq x) \prod P(U_i \leq x) =\prod x = x^n

And then cumulative distribution would be expressed like this:

0, x \leq 0

x^n, x \in (0,1)

1, x \geq 1

For each value x\in (0,1) we can find the dendity function like this:

f_X (x) = \frac{d}{dx} F_X (x) = nx^{n-1}

So then we have the pdf defined, and given by:

f_X (x) = n x^{n-1} , x \in (0,1)  and 0 for other case

And now we can find the expected value for the random variable X like this:

E(X) =\int_{0}^1 s f_X (x) dx = \int_{0}^1 x n x^{n-1}

E(X)= n \int_{0}^1 x^n dx = n [\frac{1}{n+1}- \frac{0}{n+1}]=\frac{n}{n+1}

6 0
3 years ago
Find all ratios that are equivalent to 4 : 6 and have a first term that is less than 40.
kherson [118]

Answer:

2: 3, 4: 6, 6: 9, 8: 12 , 10: 15, 12: 18, 14: 21, 16: 24, 18: 27, 20: 30, 22: 33, 24:36, 26: 39, 28: 42, 30: 45, 32: 48, 34: 51, 36: 54, 38: 57

Step-by-step explanation:

The ratio 4: 6 can be simplified to 2:3 by dividing by 2 to each side of the ratio. After simplified to 2:3, you add the ration to itself to get the rest of the terms.

7 0
3 years ago
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