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alexgriva [62]
3 years ago
13

What is the length of leg s of the triangle below

Mathematics
2 answers:
Alex787 [66]3 years ago
5 0
Pythagorean Theorem:
s^2 + 3^2 = 18
s^2 = 9
s = 3

answer is B


andrew-mc [135]3 years ago
5 0

Answer:  The correct option is (B) 3.

Step-by-step explanation:  We are given to find the length of the leg s in the triangle shown in the figure.

From the figure, we note that

the given triangle is a right-angled one, where

length of the hypotenuse, H = √18 units,

length of one leg, P = 3 units

and

length of the other leg, s = B =?.

From Pythagoras theorem, we have

H^2=P^2+B^2\\\\\Rightarrow (\sqrt{18})^2=3^2+B^2\\\\\Rightarrow 18=9+B^2\\\\\Rightarrow B^2=18-9\\\\\Rightarrow B^2=9\\\\\Rightarrow B=3.

Thus, the length of the leg s is 3 units.

Option (B) is CORRECT.

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Can someone help me please?
kati45 [8]

Answer:

4/9

Step-by-step explanation:

Find the GCD (or HCF) of numerator and denominator

GCD of 16 and 36 is 4

Divide both the numerator and denominator by the GCD

16 ÷ 4

36 ÷ 4

Reduced fraction:  

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Therefore, 16/36 simplified to lowest terms is 4/9.

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3 years ago
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Gwar [14]

Answer:

Where is the graph?

Step-by-step explanation:

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2 years ago
A metallurgist has one alloy containing 34% copper another containing 48% copper. How many pounds of each alloy must he use to m
Zielflug [23.3K]

Answer:

<h2>36.14 pounds of 34% copper alloy and 9.86 pounds of 48% copper alloy</h2>

Step-by-step explanation:

        First alloy contains 34% copper and the second alloy contains 48% alloy.

We wish to make 46 pounds of a third alloy containing 37% copper.

       Let the weight of first alloy used be x in pounds and the weight of second alloy used be y in pounds.

       Total weight = 46\text{ }pounds=x+y        -(i)

      Total weight of copper = 37\%\text{ of 46 pounds = }34\%\text{ of }x\text{ pounds + }48\%\text{ of }y\text{ pounds }

       \dfrac{37\times 46}{100}=\dfrac{34x}{100}+\dfrac{48y}{100}\\\\ 34x+48y=1702        -(ii)

       Subtracting 34 times first equation from second equation,

34x+48y-34x-34y=1702-34\times46\\14y=138\\y=9.857\text{ }pounds \\x=36.143\text{ }pounds

∴ 36.14 pounds of first alloy and 9.86 pounds of second alloy were used.

5 0
3 years ago
Ed wants to borrow $20,000 from a bank to open a small gym. Three banks charge different interest rates. To help decide the best
Delicious77 [7]

Answer:

First bank = $6792

City bank = $6803

Star bank = $6817  

Step-by-step explanation:

The lists of banks and their annual interests rates are attached.

For first bank, since the interest is 7.5%, The total interest = 7.5% of $20000 = 0.075 × $20000 = $1500

For city bank, since the interest is 8.2%, The total interest = 8.2% of $20000 = 0.082 × $20000 = $1640

For Star bank, since the interest is 9%, The total interest = 9% of $20000 = 0.09 × $20000 = $1800  

The loan plus interest for the banks annually are:

First bank = $20000 + $1500 = $21500

City bank = $20000 + $1640 = $21640

Star bank = $20000 + $1900 = $21900

The monthly payments for the banks are:

First bank = $21500 / 12 months = $1792

City bank = $21640 / 12 months = $1803

Star bank = $21800 / 12 months = $1817

Since The cost to run the gym each month is $5,000. Ed's total monthly expenses for each loan option = monthly payments + cost for each month. It is calculated as:

First bank = $5000 + $1792 = $6792

City bank = $5000 + $1803 = $6803

Star bank = $5000 + $1817 = $6817  

3 0
3 years ago
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