What is the distance, rounded to the nearest tenth, between the points (2,-2) and (6, 3)? Enter the answer in the box.
2 answers:
Answer:
d = 6.4
Step-by-step explanation:
We can use the distance formula
d =sqrt( ( y2-y1)^2 + ( x2-x1) ^2)
d =sqrt( (3 - -2)^2 + (6-2) ^2)
d =sqrt( (5)^2 + (4) ^2)
d =sqrt( 25 + 16)
d = sqrt( 41)
d =6.403124237
Rounded to the nearest tenth
d = 6.4
Using the distance formula:
Distance = sqrt((x2-x1)^2 + (y2-y1)^2)
Distance = sqrt((6-2)^2 + ( 3- -2)^2)
Distance = sqrt(4^2 + 5^2)
Distance = sqrt(16+ 25)
Distance = sqrt(41)
Distance = 6.4
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Answer:
D
Step-by-step explanation:
The answer would be 4
(Positive 4 btw)
-11.8 + 33.4y
First turn y into 1
-11.8 + 33.4 (1)
Multiply 1 by 33.4
-11.8 + 33.4
Then add
21.6
Hope this helps!!
f(x) = 3 - 2sin(x)
0 = 3 - 2sin(x)
- 3 - 3
-3 = -2sin(x)
-2 -2
1¹/₂ = sin(x)
sin⁻¹(1¹/₂) = sin⁻¹[sin(x)]
sin⁻¹(1¹/₂) = x
