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torisob [31]
3 years ago
14

What is the distance, rounded to the nearest tenth, between the points (2,-2) and (6, 3)? Enter the answer in the box.

Mathematics
2 answers:
Marina CMI [18]3 years ago
8 0

Answer:

d = 6.4

Step-by-step explanation:

We can use the distance formula

d =sqrt( ( y2-y1)^2 + ( x2-x1) ^2)

d =sqrt( (3 - -2)^2 + (6-2) ^2)

d =sqrt( (5)^2 + (4) ^2)

d =sqrt( 25 + 16)

d = sqrt( 41)

d =6.403124237

Rounded to the nearest tenth

d = 6.4

vovikov84 [41]3 years ago
6 0

Using the distance formula:

Distance = sqrt((x2-x1)^2 + (y2-y1)^2)

Distance = sqrt((6-2)^2 + ( 3- -2)^2)

Distance = sqrt(4^2 + 5^2)

Distance = sqrt(16+ 25)

Distance = sqrt(41)

Distance = 6.4

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Mrs Omar runs the school tennis club. She has a bin of tennis balls and rackets for every 5 tennis balls in the bin there are 5
irakobra [83]

Answer:

x=y

Step-by-step explanation:

-let x be the number of tennis balls and y the number of rackets.

-We divide the number of balls by the number of rackets to find out their ratio of proportionality:

\frac{x}{y}=\frac{5}{5}=\frac{1}{1}\\\\\\=>x:y

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3 years ago
a paper company needs to ship paper to a large printing business the paper will be shipped in small boxes in large boxes the vol
stepan [7]

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Step-by-step explanation:

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2 years ago
Complete the recursive formula of the geometric sequence 16\,,\,3.2\,,\,0.64\,,\,0.128,...16,3.2,0.64,0.128,
Nastasia [14]

Answer:

a_{n+1}=0.2a_n for all n>0, a_1=16

Step-by-step explanation:

Let \{a_n\}=\{16,3.2,0.64,0.128,\cdots \} be the sequence described.

A geometric sequence has the following property: there exists some r (the ratio of the sequence) such that \frac{a_{n+1}}{a_n}=r forr all n>0.

To find r, note that

\frac{3.2}{16}=\frac{32}{10(16)}=\frac{2}{10}=\frac{1}{5}=0.2

Similarly

\frac{0.64}{3.2}=\frac{64}{10(32)}=\frac{1}{5}=0.2

\frac{0.128}{0.64}=\frac{1}{5}=0.2

Thus a_{n+1}=r a_n=\frac{a_n}{5}=0.2a_n for all n>0, and a_1=16

3 0
3 years ago
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3 years ago
Solve and state any extraneous solutions
Mice21 [21]

\frac{3x}{x - 1}  + 2 =  \frac{3}{x - 1}

\frac{3x}{x - 1} +  \frac{2(x - 1) }{ x - 1}   =  \frac{3}{x - 1}

\frac{3x}{x - 1}  +  \frac{2x - 2}{ x - 1}  =  \frac{3}{x - 1}

\frac{3x + 2x - 2}{ x - 1}  =  \frac{3}{x - 1}

3x + 2x - 2 = 3

5x - 2 = 3

5x = 3 + 2

5x = 5

x =  \frac{5}{5}

x = 1

3 0
3 years ago
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