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Nata [24]
3 years ago
6

Work out the angles marked x in each diagram you must show your working

Mathematics
1 answer:
shutvik [7]3 years ago
6 0

Answer:

this how I got the answer

Step-by-step explanation:

find the angle A ..B

it's a straight line so 180.

180_148=32

In angle C..it's a full turn.so 360

360_290=70

we just have to find one more angle...

it's a straight line ..so as we know 180

32+70=102

180_102=78

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Grandpa and Grandma are treating their family to the movies. Matinee tickets cost $4 per child and $4 per adult. Evening tickets
EleoNora [17]

Complete Question

Grandpa and Grandma are treating their family to the movies. Matinee tickets cost $4 per child and $4 per adult. Evening tickets cost $6 per child and $8 per adult. They plan on spending no more than $80 on the matinee tickets and no more than $100 on the evening tickets. Could they take 9 children and 4 adults to both shows? Show your work. A yes or no answer is not sufficient for credit.

Answer:

Yes it is  possible to take the  9 children and 4 adults to both shows

Step-by-step explanation:

From the question we are told that

    The  cost of the Matinee tickets for a child is  z =  $4

    The  cost of the Matinee tickets for an adult is  a  = $ 4

     The cost of the Evening tickets for  a child is  k =  $6

      The cost of the Evening tickets for an adult is  b =  $8    

      The  maximum amount to be spent on Matinee tickets is  m = $80

       The maximum amount to be spent on Evening tickets is  e =  $100

       The  number of child to be taken to the movies is  n  = 9

        The number of adults to be taken to the movies is  j  =  4

Now the total amount of money that would be spent on Matinee tickets is  mathematically evaluated as      

           t = 4 n + 4 j

substituting values

           t = 4 *  9  + 4* 4

           t =  52

Now the total amount of money that would be spent on  Evening ticket is mathematically evaluated as      

      T =  6n + 8j

substituting values

     T =  6(9) + 8(4)

    T = 86

This implies that it is possible to take 9 children and 4 adults to both shows

given that

      t \le m

i.e  $56  \le$ 80

and  

      T \le e

i.e   $ 86 \le $ 100

4 0
3 years ago
Simplifying the following<br>expression<br>6 + 2(3-9 + 5) + (- 9)​
Verizon [17]

Answer:

-5

Step-by-step explanation:

First, distribute the 2 to the 3, -9, and 5. You will get 6 + 6 - 18 + 10 + (-9). Then, you can start from the beginning and work through combining the terms. The original equation is in bold after every step.

6 + 6 - 18 + 10 + (-9)

6+6 = 12

12 - 18 + 10 + (-9)

12-18 = -6

- 6 + 10 + (-9)

-6 + 10 = 4

4 + (-9)

4 - 9 = -5

Answer: -5

6 0
3 years ago
Can anybody help me plzz​
Fittoniya [83]

Answer:

  1 : 12 : 4

Step-by-step explanation:

Let A, G, C represent the ages of Alex, George, and Carl, respectively. We are told that ...

  A = G +12

  C = 3A . . . . . . . we read this as "3 times as old"; not "3 times older"

  A + G + C = 68

Substituting for G and C, we have ...

  A + (A -12) +(3A) = 68

  5A = 80 . . . . . add 12

  A = 16 . . . . . . . divide by 5

The other ages are then ...

  G = A-12 = 16 -12 = 4

  C = 3A = 3·16 = 48

The ratios are ...

  G : C : A = 4 : 48 : 16

  G : C : A = 1 : 12 : 4

7 0
3 years ago
John plays basketball at the local gym. The gym charges a monthly membership fee of $15.00, plus each player pays $2.50 per game
Katyanochek1 [597]
Answer:
Step-by-step explanation:
Assuming that for each option, you play the same number of games,x
Let y represent the cost of playing x games using option A
Option A is to buy a membership card and pay $2 every time you go to the gym. The membership card costs $20. It means that
y = 20 + 2x
Let z represent the cost of playing x games using option B
Option B is to pay $4 each time you go. It means that
z = 4x
To determine how many games will be played before cost of option A equal to the cost of option B, we would equate y to z. It becomes
20 + 2x = 4x
4x - 2x = 20
2x = 20
x = 20/2 = 10
It will take 10 games for both to be the same
3 0
3 years ago
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How to find the asymtope of a function
Darya [45]
Asymptote at x = 3 and a horizontal asymptote at y = 1. The curves approach these asymptotes but never cross them. The method used to find the horizontal asymptote changes depending on how the degrees of the polynomials in the numerator and denominator of the function compare.
3 0
3 years ago
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