How do i solve for the variables

If one minor arc is 112°, what is the measure of the remainder of the circle?

miss Akunina [59]

Answer:

∴ The measure of the remainder of the circle = 248°

Step-by-step explanation:

∵ The measure of the circle = 360°

∵ The measure of the minor arc = 112°

∴ The measure of the remainder of the circle = 360 - 112 = 248°

7 0

4 years ago

A grocery sold 5kg of wheat flour at Rs30 per kg and gained 20%. If he had sold it at Rs27 per kg, what would be his gain or los

maria [59]

Answer:

His gain percent would have been 8%

Step-by-step explanation:

The key to answering this question is to first calculate the price at which the wheat flour was bought.

Mathematically;

% profit = (selling price-cost price)/cost price * 100%

Let the cost price be $x

Thus;

% profit = (30-x)/x * 100

20 = 100(30-x)/x

20x = 3000-100x

100x + 20x = 3000

120x = 3000

x = 3000/120

x = Rs 25

So let’s assume he sold at Rs 27

His profit would have been 27-25 = 2

His gain or loss percentage would’ve been;

2/25 * 100/1 = 200/25 = 8% (gain, since selling price is greater than the cost price)

3 0

3 years ago

a rectangular fish tank 60 centimeters by 15 centimeters by 34 centimeters is 1/3 full of water. find the volume of water needed

son4ous [18]

Answer:

$20,400\ cm^{3}$

Step-by-step explanation:

step 1

Find the volume of the tank

$V=(60)(15)(34)=30,600\ cm^{3}$

step 2

we know that

If the tank is 1/3 full of water

then

the volume of water required to completely fill the tank is equal to 2/3 of the tank capacity

so

$(2/3)30,600=20,400\ cm^{3}$

5 0

3 years ago

The two box plots summarize the number of hours spent in the weight room for all the players on the football team

iragen [17]

Options:

A. Players at school 1 typically spent more time in the weight room than players at school 2.

B. The middle half of the data for school 1 has more variability than the middle half of the data for school 2.

C. The median hours spent in the weight room for school 1 is less than the median for school 2 and the interquartile ranges for both schools are equal.

D. The total number of hours spent in the weight room for players at school 2 is greater than the total number of hours for players at school 1.

(See attachment for the box plots)

Answer:

C. The median hours spent in the weight room for school 1 is less than the median for school 2 and the interquartile ranges for both schools are equal.

Step-by-step explanation:

The median for school 1 is the value at the vertical line that divides the box of the box plot display of for school 1, which is 8

School 2 has a median of 9.

As we can see, the median for school 1 is less than the median of school 2.

Interquartile range is the range of the box.

Interquartile range for school 1 = 10 - 4 = 6

Interquartile range for school 2 = 13 - 6 = 6

As we can also see, the interquartile range for school 1 and that of school 2 are equal.

7 0

4 years ago

A bag has 30 tiles. Numbered 1-30. Perfect squares to non-perfect squares . Write ratio in simplest form .

Rudiy27

Answer:

Ratio = $\frac{Perfect.squares}{non.Perfect.squares}$ = $\frac{1}{5}$

Step-by-step explanation:

The perfect squares from 1-30 are:

1, 4, 9, 16, 25

Total no. of perfect squares = five =5

Total no. of non perfect squares = 30-5 = 25

Ratio = $\frac{Perfect.squares}{non.Perfect.squares}$ = 5 / 25 = $\frac{1}{5}$

3 0

3 years ago