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4 years ago

Write fraction as decumal 3 and 3 over 4

Mathematics

1 answer:

sattari [20]4 years ago

3 0

Hi there!

~

To turn $3\frac{3}{4}$ to a decimal, you must first convert it to an improper fraction, to do that you multiply the whole number (3) and the denominator (4).

$4$ × $3$ $= 12$

Then you add the product of 3 and 4 (12) to the numerator (3).

$3 + 12 = 15$

You then make the sum of the numerator and the product of the whole number and denominator into the numerator.

This leaves us with : $\frac{15}{3}$

Hope this helped you!

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You need $40 $ 40 to buy a new pair of shoes. You have saved $15 $ 15 . Which inequality models how much more you must save?

Hoochie [10]

Answer:

40 < 15+x

Step-by-step explanation:

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3 years ago

Solve for x-7/2=3/10

Marysya12 [62]

The answer for this would be x= 38/5

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4 years ago

Read 2 more answers

In an arithmetic sequence, = 5 and = 11.

Free_Kalibri [48]

Answer:

1134.62 (THE SUM OF 20 TERMS)

Step-by-step explanation:

First we write out our given information:

a8=2a2

a11=18

an is an arithmetic sequence.

Where here an means the nth term of our sequence.

What does an arithmetic sequence mean? It means to get to the next term in your sequence you add a constant (c) each time:

an+1=an+c

Equivalently:

an+1−an(n+1)−n=c

So an is of slope c (c2 is another constant):

an=cn+c2

Where here c2=a0 (Substitute in n=0 and see why that has to be the case if we let a0 exist)

Now we use the other given information to try to come up with a solution.

Let n=2:

a2=2c+c2

Let n=8, using the above equation we have:

a8=8c+c2=2a2=4c+2c2

Let n=11

a11=18

a11=11c+c2

But a11−a8=(11c+c2)−(8c+c2)=3c

Hence, a11=3c+a8

a11=3c+4c+2c2=18

a11=3c+8c+c2=18

5 0

3 years ago

An investigator thinks that people under the age of forty have vocabularies that are different than those of people over sixty y

Kay [80]

Answer:

$t=\frac{(14-20)-0}{\sqrt{\frac{5^2}{31}+\frac{6^2}{31}}}}=-4.28$

Now we can calculate the p value with the following probability:

$p_v =2*P(t_{60}$

The p value is a very low value so then we have enough evidence to reject the null hypothesis and we can conclude that people under the age of forty have vocabularies that are different than those of people over sixty years of age.

Step-by-step explanation:

Information given

$\bar X_{1}=14$ represent the mean for sample 1 (younger)

$\bar X_{2}=20$ represent the mean for sample 2 (older)

$s_{1}=5$ represent the sample standard deviation for 1

$s_{f}=6$ represent the sample standard deviation for 2

$n_{1}=31$ sample size for the group 2

$n_{2}=31$ sample size for the group 2

t would represent the statistic

System of hypothesis

We want to test if that people under the age of forty have vocabularies that are different than those of people over sixty years of age, the system of hypothesis are:

Null hypothesis: $\mu_{1}-\mu_{2}=0$

Alternative hypothesis: $\mu_{1} - \mu_{2}\neq 0$

The statistic is given by:

$t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

And the degrees of freedom are given by $df=n_1 +n_2 -2=31+31-2=60$

Replacing the info given we got:

$t=\frac{(14-20)-0}{\sqrt{\frac{5^2}{31}+\frac{6^2}{31}}}}=-4.28$

Now we can calculate the p value with the following probability:

$p_v =2*P(t_{60}$

6 0

3 years ago

How many zeros are in the product of any nonzero whole number less than 10 and 500

worty [1.4K]

Answer:

If the non-zero whole number is even, then there are 3 zeroes

If the non-zero whole number is odd, then there are 2 zeroes

Step-by-step explanation:

* Lets explain the information in the problem

- Whole numbers are positive numbers, including zero, without

any decimal or fractional

- Nonzero whole numbers are positive numbers, not including zero

- The non-zero whole numbers less then 10 are:

1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9

- The product of any nonzero whole number less than 10 and 500

means multiply any of nonzero number above by 500

- The number of zeros in the product is equal to the sum of the

number of zeros at the end of each of the factors.

# 1 × 500 = 5 × 100 ⇒ 2 zeros

# 2 × 500 = 2 × 5 × 100 = 10 × 100 ⇒ 3 zeros

# 3 × 500 = 3 × 5 × 100 = 15 × 100 ⇒ 2 zeros

# 4 × 500 = 2 × 2 × 5 × 100 = 2 × 10 × 100 ⇒ 3 zeros

# 5 × 500 = 5 × 5 × 100 = 25 × 100 ⇒ 2 zeroes

# 6 × 500 = 2 × 3 × 5 × 100 = 3 × 10 × 100 ⇒ 3 zeros

# 7 × 500 = 7 × 5 × 100 = 35 × 100 ⇒ 2 zeroes

# 8 × 500 = 2 × 2 × 2 × 5 × 100 = 4 × 10 × 100 ⇒ 3 zeros

# 9 × 500 = 3 × 3 × 5 × 100 = 45 × 100 ⇒ 2 zeros

- From all answers above:

# If the non-zero whole number is even (2 , 4 , 6 , 8), then there are

3 zeros in the product

# If the non-zero whole number is odd (1 , 3 , 5 , 7 , 9), then there are

2 zeros in the product

8 0

3 years ago

Write fraction as decumal 3 and 3 over 4​

Write fraction as decumal 3 and 3 over 4