Hello!
Your answer is:
x-31 ≥ 66⇒x ≥ 97!
Hopefully this helps! Please correct me if im wrong! :C
Answer:
7 tenths -> 7/10, that's it
Answer: True
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Work Shown:
Follow PEMDAS in reverse to solve for q
22q - 7 < 37
22q - 7+7 < 37+7 ... add 7 to both sides
22q < 44
22q/22 < 44/22 ... divide both sides by 22
q < 2
Answer:
12. 1 second, 35 ft; 2 seconds, 32 ft
13. (t, y) = (1.4 seconds, 37.6 feet)
14. 37.6 ft; the vertex is the highest point
Step-by-step explanation:
12. You have properly answered question 12.
After 1 second, the height is 35 feet; after 2 seconds, it is 32 feet.
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13. My method of choice is to plot the graph on a graphing calculator and let it show me the coordinates of the vertex when I highlight that point. (See attached.) The vertex is ...
(t, y) = (1.4, 37.6)
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14. The graph is a graph of height when the object is launched with a vertical velocity of 45 ft/s. So, the maximum of the graph will correspond to the maximum height of the object. The vertex is that maximum point, and its y-coordinate is that maximum height.
The maximum height is 37.6 feet.
Obtuse angles are over 90 degrees but less than 180 degrees. So minimum y can be is 10: (5 x 10) + 45 = 95 degrees (which is more than 90). Maximum for y is 26: (5 x 26) + 45 = 175 (which is less than 180 degrees)