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Amiraneli [1.4K]
3 years ago
6

EVALAUTE: 5|7 - 9| - 2= a. -12 b. 0 c. 1 d. 8

Mathematics
1 answer:
alexandr1967 [171]3 years ago
3 0
It’s d!!!!!!!!!!!!!!
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Ur answer is 1369 that is ur answer hope it helped and hope u pass
 


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What is the density of a paperclip with a volume of 2 ml and a mass of 3 grams?
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Answer:

1.5 grams per millimeters cubed

Step-by-step explanation:

The formula for density is D=M÷V

Just divide 3 by 2 and you are done.

4 0
2 years ago
The triangles shown below must be congruent
Leokris [45]

Yes; they  have the same side lengths and angles

8 0
2 years ago
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How to do this step by step
Marina CMI [18]

1. 36 = 6·6 and 42 = 6·7 have a common factor of 6.

... x⁴ and x² have a common factor of x²

The GCF is 6x².

The factorization is 36x⁴ -42x² = 6x²(6x² -7)

2. All coefficients are multiples of 4. All variable factors are multiples of x³.

The GCF is 4x³.

The factorization is 4x⁵ -8x⁴ -4x³ = 4x³(x² -2x -1)

3. The GCF of coefficients 6 and 15 is (15 mod 6) = 3, which is also a factor of the other coefficients. The lowest power of m, which is m² is also a factor of the other terms.

The GCF is 3m².

The factorization is 6m⁵ -15m⁴ -21m³ +27m² = 3m²(2m³ -5m² -7m +9)

5 0
3 years ago
Brandon is on one side of a river that is 50 m wide and wants to reach a point 300 m downstream on the opposite side as quickly
AlexFokin [52]
Let P be Brandon's starting point and Q be the point directly across the river from P. 
<span>Now let R be the point where Brandon swims to on the opposite shore, and let </span>
<span>QR = x. Then he will swim a distance of sqrt(50^2 + x^2) meters and then run </span>
<span>a distance of (300 - x) meters. Since time = distance/speed, the time of travel T is </span>

<span>T = (1/2)*sqrt(2500 + x^2) + (1/6)*(300 - x). Now differentiate with respect to x: </span>

<span>dT/dx = (1/4)*(2500 + x^2)^(-1/2) *(2x) - (1/6). Now to find the critical points set </span>
<span>dT/dx = 0, which will be the case when </span>

<span>(x/2) / sqrt(2500 + x^2) = 1/6 ----> </span>

<span>3x = sqrt(2500 + x^2) ----> </span>

<span>9x^2 = 2500 + x^2 ----> 8x^2 = 2500 ---> x^2 = 625/2 ---> x = (25/2)*sqrt(2) m, </span>

<span>which is about 17.7 m downstream from Q. </span>

<span>Now d/dx(dT/dx) = 1250/(2500 + x^2) > 0 for x = 17.7, so by the second derivative </span>
<span>test the time of travel, T, is minimized at x = (25/2)*sqrt(2) m. So to find the </span>
<span>minimum travel time just plug this value of x into to equation for T: </span>

<span>T(x) = (1/2)*sqrt(2500 + x^2) + (1/6)*(300 - x) ----> </span>

<span>T((25/2)*sqrt(2)) = (1/2)*(sqrt(2500 + (625/2)) + (1/6)*(300 - (25/2)*sqrt(2)) = 73.57 s.</span><span>
</span><span>
</span><span>
</span><span>
</span><span>mind blown</span>
8 0
3 years ago
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