Answer:Include
Step-by-step explanation:
Multiply add and subtract the top. I can include the rest if you want
Answer:
(x+12)(x+5)
Step-by-step explanation:
Formula use: a²+bx+c
- Make one side equal to zero:
Original:
-7x-60 =x² +10x
New:
x² + 17x + 60
New:
(1)x x 60 = 60
- Find factors of 60 that when added, equal to 17.
New:
10 × 6, 60 × 1, 20 × 3, <u>5 × 12</u>, 4 × 15
5 times 12 equal 60, but when added equal to 17.
- Replace the 17 with 5 and 12
New:
x² + 5x + 12x + 60
- Break them off into two equations
New:
x² + 5x l 12x + 60
- Divide each equation into it's simpilest form. Make sure the numbers in the ( ) are the same.
New:
x(x + 5) l +12(x+5)
Given: A =( 2 , 4 , 6 , 18 , ) B = ( 2 , 4 , 6 , 8 , ) C = ( 4 , 10 , 12 , ) What is A U B C?
Anni [7]
2,4,6,8,10,12,18 is the answer
Answer:
Since 10/9 is greater than 1, multiplying by 10/9 makes the value larger
Step-by-step explanation:
Step 1: Solve the fraction
10/9 = 1.1112
Therefore 10/9 > 1
Step 2: Multiple the fraction by itself
10/9 x 10/9 = 100/81
Convert fraction to decimals
100/81 = 1.2345678901.....
1.234567901 > 1.1112
Therefore 10/9 x 10/9 is bigger than 10/9
6.3 many more cups of dry food will Maria's pet have eaten than Trenton's pet will have eaten over 2 seven-day weeks
<u>Step-by-step explanation:</u>
We have , Trenton and Maria record how much dry food their pets eat on average each day.• Trenton's pet: 4/5 cup of dry food• Maria's pet: 1.25 cups of dry food. Based on these averages . We need to find how many more cups of dry food will Maria's pet have eaten than Trenton's pet will have eaten over 2 seven-day weeks . We need to find how much they eat for 14 days as:
Trenton's pet: 4/5 cup of dry food•
With 4/5 per day , for 14 days :
⇒ 
⇒ 
⇒ 
Maria's pet: 1.25 cups of dry food.
With 1.25 per day , for 14 days :
⇒ 
⇒ 
Subtracting Maria's - Trenton's :
⇒ 
That means , 6.3 many more cups of dry food will Maria's pet have eaten than Trenton's pet will have eaten over 2 seven-day weeks
