How to solve negative exponents? (Extended,long)
1 answer:
Easily, you write the inverse of it without a minus
so if you were to find x^(-2) it would be (1/x)^2
The rest is all the same
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Answer:
x > 5
Step-by-step explanation:
x-8>-3
Add 8 to each side
x-8+8>-3+8
x > 5
Im not sure cuz i learned this for long time ago
but i think 5 is 1
and 7 might be2
i have no idea for 8
im sorry :/
0.833333… it goes on forever
ax - b = c
add b to each side
ax-b +b = c+b
ax = c+b
divide by a
ax/a = (c+b)/a
x = (c+b)/a
