4 years ago

What are zeros of f(x) = (x-3)(x+8)?

Mathematics

1 answer:

Oduvanchick [21]4 years ago

5 0

Answer:

The zeros are -8,3

Step-by-step explanation:

We can use the zero product property which says set each of the factors equal to zero

0 = (x-3)(x+8)

x-3 = 0 x+8 = 0

x-3+3=0=3 x+8-8 = 0-8

x= 3 x = -8

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