3 years ago

What are zeros of f(x) = (x-3)(x+8)?

Mathematics

1 answer:

Oduvanchick [21]3 years ago

5 0

Answer:

The zeros are -8,3

Step-by-step explanation:

We can use the zero product property which says set each of the factors equal to zero

0 = (x-3)(x+8)

x-3 = 0 x+8 = 0

x-3+3=0=3 x+8-8 = 0-8

x= 3 x = -8

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ABCD is a rectangle ,its diagonals meet at O.If AO = 5x+1 and BO = 4x+9,find the length of the diagonals .(lengths in cm).

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Step-by-step explanation:

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2 years ago

What is the nth term of the geometric sequence -2,10,-50

poizon [28]

Answer:

$T_n=-1(-5)^n^-^1$

Step-by-step explanation:

We are given;

A geometric sequence;

-2,10,-50

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The nth term in a geometric sequence is given by the formula;

$T_n=a_1r^n^-^1$

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In this case;

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To get the nth term in the given geometric sequence we use;

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