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3 years ago

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A pizza restaurant has 21 topping choices and 3 crust choices. How many different 3-topping pizzas can be made if toppings can b

e selected more than once?

2 answers:

aliya0001 [1]3 years ago

8 0

It is 27, 783. Hope this helps

katen-ka-za [31]3 years ago

3 0

Answer: 27783

Step-by-step explanation:

Given : The number of toppings for pizza= 21

If repetition of toppings is allowed, then the number of different 3-topping combinations will be :-

$21\times21\times21=9261$

Also, the number of choices for crust = 3

Then, the number if different 3-topping pizzas can be made if toppings can be selected more than once will be :_

$9261\times3=27783$

Hence, the number of different 3-topping pizzas can be made = 27783

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Compare the perimeters of the two regular figures. Which statement is true?

adell [148]

Answer:

(A). The perimeter of the octagon is greater than that of the hexagon.

Step-by-step explanation:

Since, hexagon consists of 6 sides and 6 angles, thus the measure of one angle of the hexagon will be= $\frac{(n-2){\timeS}180^{\circ}}{6}$

= $\frac{(6-2){\timeS}180^{\circ}}{6}$

= $\frac{(4){\timeS}180^{\circ}}{6}$

= $120^{\circ}$

Now, since MQ is the angle bisector of the one of the angle of the hexagon, therefore ∠QMP=60°.

Now, from ΔQMP. we have

$\frac{MP}{MQ}=cos60^{\circ}$

$MP=\frac{1}{2}$

Thus, the perimeter of the hexagon is:

$P=12{\times}MP$

$P=12{\times}\frac{1}{2}$

$P=6 units$

Thus, the perimeter of hexagon is 6 units.

Also, Since, octagon consists of 8 sides and 8 angles, thus the measure of one angle of the octagon will be= $\frac{(n-2){\timeS}180^{\circ}}{8}$

= $\frac{(8-2){\timeS}180^{\circ}}{8}$

= $\frac{(6){\timeS}180^{\circ}}{8}$

= $135^{\circ}$

Now, since AP is the angle bisector of the one of the angle of the octagon, therefore ${\angle}PAC=cos\frac{135}{2}$ .

From ΔAPC, we have

$AC=cos\frac{135}{2}$

Now, Perimeter of octagon is:

$P=16{\times}cos\frac{135}{2}$

$P=16{\times}0.382$

$P=6.122 units$

Thus, the perimeter of octagon is 6.122 units.

Now, the perimeter of octagon is greater than perimeter of the hexagon, thus option A is correct that is The perimeter of the octagon is greater than that of the hexagon.

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Natalija [7]

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Step-by-step explanation:

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svlad2 [7]

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Firdavs [7]

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icang [17]

Answer:

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