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svet-max [94.6K]
3 years ago
9

Which is the more reasonable temperature for a snowy day: 30° C or 30° F?

Mathematics
2 answers:
andrew-mc [135]3 years ago
6 0
The more reasonable temperature is 30°F
melisa1 [442]3 years ago
4 0

Answer:

30° F

Step-by-step explanation:

30° F is the more reasonable temperature for a snowy day.

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Use a graphing calculator to solve the equation 3 tan 1/3 (theta) =8 in the interval 2 to pie.
abruzzese [7]
The answer to this may be C
3 0
3 years ago
Calculate s f(x, y, z) ds for the given surface and function. g(r, θ) = (r cos θ, r sin θ, θ), 0 ≤ r ≤ 4, 0 ≤ θ ≤ 2π; f(x, y, z)
Triss [41]

g(r,\theta)=(r\cos\theta,r\sin\theta,\theta)\implies\begin{cases}g_r=(\cos\theta,\sin\theta,0)\\g_\theta=(-r\sin\theta,r\cos\theta,1)\end{cases}

The surface element is

\mathrm dS=\|g_r\times g_\theta\|\,\mathrm dr\,\mathrm d\theta=\sqrt{1+r^2}\,\mathrm dr\,\mathrm d\theta

and the integral is

\displaystyle\iint_Sx^2+y^2\,\mathrm dS=\int_0^{2\pi}\int_0^4((r\cos\theta)^2+(r\sin\theta)^2)\sqrt{1+r^2}\,\mathrm dr\,\mathrm d\theta

=\displaystyle2\pi\int_0^4r^2\sqrt{1+r^2}\,\mathrm dr=\frac\pi4(132\sqrt{17}-\sinh^{-1}4)

###

To compute the last integral, you can integrate by parts:

u=r\implies\mathrm du=\mathrm dr

\mathrm dv=r\sqrt{1+r^2}\,\mathrm dr\implies v=\dfrac13(1+r^2)^{3/2}

\displaystyle\int_0^4r^2\sqrt{1+r^2}\,\mathrm dr=\frac r3(1+r^2)^{3/2}\bigg|_0^4-\frac13\int_0^4(1+r^2)^{3/2}\,\mathrm dr

For this integral, consider a substitution of

r=\sinh s\implies\mathrm dr=\cosh s\,\mathrm ds

\displaystyle\int_0^4(1+r^2)^{3/2}\,\mathrm dr=\int_0^{\sinh^{-1}4}(1+\sinh^2s)^{3/2}\cosh s\,\mathrm ds

\displaystyle=\int_0^{\sinh^{-1}4}\cosh^4s\,\mathrm ds

=\displaystyle\frac18\int_0^{\sinh^{-1}4}(3+4\cosh2s+\cosh4s)\,\mathrm ds

and the result above follows.

4 0
3 years ago
If Kiran solves the equation for p, which equation would result?
pav-90 [236]

Answer:  i have a answer but it is not up there srry

Step-by-step explanation:  

3 0
2 years ago
Solve the following equation. then place the correct number in the box provided. 2x + 1 < 9
allsm [11]
I think the answer is 4
8 0
2 years ago
Here is your questions
viva [34]

Answer:

Step-by-step explanation:

strategy:  find the distance of the two points,   take half of that,  b/c that will be the radius,   Then use   the area of a circle formula to find the answer

P1 = (1,-1)   in the form (x1,y1)

P2= ((3,3)  in the form (x2,y2)

dist = sqrt [ (x2-x1)^2 + (y2-y1)^2 ]

dist = sqrt [ 3 -1 )^2 + 3-(-1)^2 ]

dist = sqrt [ 2^2 + 4^2 ]

dist = sqrt [ 4 + 16 ]

dist = sqrt [20]

r = \sqrt{20} /2

area of circle = \pir^{2}

area of circle = \pi(\sqrt{20} /2)^2

area of circle = \pi(\sqrt{20} /2)(\sqrt{20} /2)

area of circle = \pi(20 / 4)

area of circle = \pi5

area of circle = 5\pi

3 0
2 years ago
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