Answer:
The 99% confidence interval for the proportion of readers who would like more coverage of local news is (0.3685, 0.4315).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
For this problem, we have that:
99% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
The lower limit of this interval is:
The upper limit of this interval is:
The 99% confidence interval for the proportion of readers who would like more coverage of local news is (0.3685, 0.4315).
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Answer:
99
Step-by-step explanation:
99 x 33 x 3 can be simplified to 99 x 99. If you square root this you will end up with 99
Honestly I don't know congruent so congrats I can't answer sorry
She worked 30 hours per week.
The problem turns out to be the following:
2x+15=3x-15.
First you need to have only one x variable so you subtract the X's:
3x-2x=X
The problem now turns into 15=x-15.
You have to isolate the X so you do x+15. You have to do the same to the other side so 15+15=30, therefore x=30
