Answer: All of the numbers in the sequence are going up twice the amount as before. The next three terms will be 208, 416, 832
Step-by-step explanation:
consider k the numbe of correct answers
P(k) = kC8×(0,2)^k×(0,8)^(8-k)
example:
The probability of having 2 correct answers = 2C8×(0,2)^2×(0,8)^(6) = 0.294
the probability that the number x or correct answer is fewer than 4 =
p(0) + p(1) + p(2) + p(3) = 0.944
Combine like terms.
-x + Q - 10
(I don’t think the order of terms matters)
Answer:
a) P(Y > 76) = 0.0122
b) i) P(both of them will be more than 76 inches tall) = 0.00015
ii) P(Y > 76) = 0.0007
Step-by-step explanation:
Given - The heights of men in a certain population follow a normal distribution with mean 69.7 inches and standard deviation 2.8 inches.
To find - (a) If a man is chosen at random from the population, find
the probability that he will be more than 76 inches tall.
(b) If two men are chosen at random from the population, find
the probability that
(i) both of them will be more than 76 inches tall;
(ii) their mean height will be more than 76 inches.
Proof -
a)
P(Y > 76) = P(Y - mean > 76 - mean)
= P( ) > )
= P(Z > )
= P(Z > )
= P(Z > 2.25)
= 1 - P(Z ≤ 2.25)
= 0.0122
⇒P(Y > 76) = 0.0122
b)
(i)
P(both of them will be more than 76 inches tall) = (0.0122)²
= 0.00015
⇒P(both of them will be more than 76 inches tall) = 0.00015
(ii)
Given that,
Mean = 69.7,
= 1.979899,
Now,
P(Y > 76) = P(Y - mean > 76 - mean)
= P( )) > )
= P(Z > )
= P(Z > ))
= P(Z > 3.182)
= 1 - P(Z ≤ 3.182)
= 0.0007
⇒P(Y > 76) = 0.0007
Deal with the numbers first
GCF of 16, 40 and 68 is 4
there is no GCF of the variables
so required GCF is 4