According to Sturge's rule, number of classes or bins recommended to construct a frequency distribution is k ≈ 7
Sturge's Rule: There are no hard and fast guidelines for the size of a class interval or bin when building a frequency distribution table. However, Sturge's rule offers advice on how many intervals one can make if one is genuinely unable to choose a class width. Sturge's rule advises that the class interval number be for a set of n observations.
Given,
n = 66
We know that,
According to Sturge's rule, the optimal number of class intervals can be determined by using the equation:
Here, n is equal to 66 and by substituting the value to the equation we get:
k = 7.0444
k ≈ 7
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Answer:
The complete list of factors for 805 are 1, 5, 7, 23, 35, 115, 161, and 805.
Step-by-step explanation:
A factor pair is a combination of two factors which can be multiplied together to equal 805. In proper math terms, the number 805 is called the product and the two numbers that can be multiplied together to equal it are called the factors.
In order to work out the factor pairs of 805 we need to first get all of the factors of 805. Once you have the list of all those factors we can pair them together to list out all of the factor pairs.
The complete list of factors for 805 are 1, 5, 7, 23, 35, 115, 161, and 805.
Answers 5x=d that’s the answer nothing else
Since x=-10, plug that into the equation.
f(x) = 2(-10) + 11
= -20 + 11
y = -9
So the ordered pair in (x,y) terms is (-10,-9).
The answer is 6/5 (six over five) 100 divided by 20
