First answer gets 20 points and brainliest question

A bag contains 6 red balls 8 yellow ones and 4 black ones if a ball is randomly selected find the probability of it being neithe

Natali [406]

Answer:

1/3

(given answers in Question are unreadable)

Step-by-step explanation:

We search for red balls (neither yellow or black). There are 6 red balls among all 18 balls. Selecting one ball, there is a chance 6/18 that we pull out a red one. 6/18 is the same as 1/3.

3 0

3 years ago

The first term in a sequence is 3<br> The term-to-term rule is + 8<br> What is the 5th term?

galben [10]

2nd term: 3+8
= 11
3rd term: 11+8
= 19
4th term: 19+8
= 27
5th term: 27+8
= 35

OR
((n-1)x8)+3

7 0

2 years ago

PLEASE HELP ME WITH THIS! A flower bed is in the shape of a triangle with one side twice the length of the shortest side, and t

LUCKY_DIMON [66]

Answer:

A=60, B=80, and C=67

Step by step explanation:

B= 2a

C= a+27

With the information, you get the equation:

A+A+27+2A=187

Then, you have to simplify.

You then get 4a+27=187.

Now, you subtract 27 from both sides to get: 4a=60.

Divide both sides by 4 to get A= 60.

If A=60, 2A=80, so B=80. A+27=67, so C=67.

You check this by adding them up to see if they equal to 187, which in fact, they do.

A=60, B=80, and C=67.

Hope this helped!

7 0

3 years ago

WARNJNG ⚠️⚠️ just help me please

marta [7]

(4)3 is also the same thing as 4x3 which is 12n

5 0

2 years ago

Arm Span(x) Height(y)

natita [175]

Answer:

Here's what I get.

Step-by-step explanation:

1. Representation of data

I used Excel to create a scatterplot of the data, draw the line of best fit, and print the regression equation.

2. Line of best fit

(a) Variables

I chose arm span as the dependent variable (y-axis) and height as the independent variable (x-axis).

It seems to me that arm span depends on your height rather than the other way around.

(b) Regression equation

The calculation is easy but tedious, so I asked Excel to do it.

For the equation y = ax + b, the formulas are

$a = \dfrac{\sum y \sum x^{2} - \sum x \sumxy}{n\sum x^{2}- \left (\sum x\right )^{2}}\\\\b = \dfrac{n\sumx y - \sum x \sumxy}{n\sum x^{2}- \left (\sum x\right )^{2}}$

This gave the regression equation:

y = 1.0595x - 4.1524

(c) Interpretation

The line shows how arm span depends on height.

The slope of the line says that arm span increases about 6 % faster than height.

The y-intercept is -4. If your height is zero, your arm length is -4 in (both are impossible).

(d) Residuals

$\begin{array}{cccr}&\textbf{Arm Span} & \textbf{Arm Span}&\\\textbf{Height/in} &\textbf{Actual} & \textbf{Predicted}&\textbf{Residual}\\25 & 19 & 22.3 & -3.3\\40 & 41 & 38.2 & 2.8\\55 & 51 & 54.1 & -3.1\\65 & 67 & 62.6 & 4.4\\ \end{array}$

The residuals appear to be evenly distributed above and below the predicted values.

A graph of all the residuals confirms this observation.

The equation usually predicts arm span to within 4 in.

(e) Predictions

(i) Height of person with 66 in arm span

$\begin{array}{rcl}y& = & 1.0595x - 4.1524\\66 & = & 1.0595x - 4.1524\\70.1524 & = & 1.0595x\\x & = & \dfrac{70.1524}{1.0595}\\\\& = & \textbf{66 in}\\\end{array}\\\text{A person with an arm span of 66 in should have a height of about $\large \boxed{\textbf{66 in}}$}$

(ii) Arm span of 74 in tall person

$\begin{array}{rcl}y& = & 1.0595x - 4.1524\\& = & 1.0595\times74 - 4.1524\\& = & 78.4030 - 4.1524\\& = & \textbf{74 in}\\\end{array}\\\text{ A person who is 74 in tall should have an arm span of $\large \boxed{\textbf{74 in}}$}$

6 0

3 years ago