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STatiana [176]
3 years ago
12

Yash wants to prove that KA=KC. To do that, he decides to prove that△KAB≅△KCB. Which theorem or postulate can Yash use to prove

the triangles congruent?
Hypotenuse-Leg (HL) Congruence TheoremSide-Side-Side (SSS) Congruence PostulateAngle-Angle-Side (AAS) Congruence TheoremSide-Angle-Side (SAS) Congruence Postulate

Mathematics
1 answer:
marta [7]3 years ago
6 0

Observe the figure clearly.

To Prove: KA = KC

Proof:

Consider the triangles \Delta KAB , \Delta KCB

KB = KB (Common side)

\angle KAB = \angle KCB (each angle is of 90 degree)

\angle ABK = \angle KBC (As BY bisects angle ABC)

Therefore, \Delta KAB \cong \Delta KCB

By AAS congruence Theorem which states:

"If two angles and a non-included side of one triangle are congruent to the corresponding parts of another triangle, then the triangles are congruent".

Hence, the given triangles are congruent by AAS congruence criteria.

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4 0
2 years ago
Answer for number 12
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Answer:

12 a. 4605 feet 12 b. 1,459,063 square feet

Step-by-step explanation:

For the perimeter, we simply add the lengths of each of the 5 sides together (or multiply 5 times one side length).

P = 5(921)

P = 4605 feet

For the area, we will use composition...add the area of the triangle to the area of the trapezoid.

For the area of the triangle, the formula is

A=\frac{1}{2}bh.

Filling in our values gives us

A=\frac{1}{2}(1490)(541) and

A = 403,045 square feet.

Now for the trapezoid.  The formula for a trapezoid is

A=\frac{1}{2}(b_{1}+b_{2})(h)

where the b's represent the bases and the h represents the height.  Filling in our values gives us

A=\frac{1}{2}(921+1490)(876)

Work inside the parenthesis first:

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