PLEASE HELP MEEE Write a linear function that related y to x

Which inequality is represented by this graph? 0 - 345> x O 0 -34.5 0 -355 cx

julia-pushkina [17]

Answer:

Step-by-step explanation:

If x is the white dot on the graph:

From what it looks like, x is right between -35 and -34 x (which is -35.5).

If that is the case then none of the answers are correct since -35.5 is equal or less than x. (the sign looks like this: " $\leq$ " )

But if you have to choose one of the answers then number 4 (-35.5 < x) would be closest.

8 0

3 years ago

What is |3| - 7...............

Ad libitum [116K]

The absolute value of 3 =3
So 3-7= -4

6 0

3 years ago

Marcus bought a booklet of tickets to use at the amusement park. He used 25% of the tickets on rides, 1/4 of the tickets on vide

Jobisdone [24]

Answer:

Step-by-step explanation:

6 0

3 years ago

Write the quadratic equation y= x^2 -6x = 7 in vertex form.

lapo4ka [179]

Answer:

(x - 3)² - 16 = 0

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Subtract 7 from both sides

x² - 6x + 7 = 0 ← in standard form

with a = 1, b = - 6

Given a quadratic in standard form then the x- coordinate of the vertex is

$x_{vertex}$ = - $\frac{b}{2a}$ = - $\frac{-6}{2}$ = 3

Substitute x = 3 into the equation for y

y = 3² - 6(3) - 7 = 9 - 18 - 7 = - 16 ⇒ (h, k) = (3, - 16)

y = (x - 3)² - 16 = 0

7 0

3 years ago

WHO CAN solve it Please !

Mariulka [41]

Answer:

a) True

$\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha } )d\alpha =0$

Step-by-step explanation:

Step(i):-

Given that the definite integration

$\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha } )d\alpha$

we know that the trigonometric formula

sin²∝+cos²∝ = 1

cos²∝ = 1-sin²∝

step(ii):-

Now the integration

$\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha } )d\alpha = \int\limits^\pi _0 {(\sqrt{cos^{2} \alpha } } \, )d\alpha$

= $\int\limits^\pi _0 {cos\alpha } \, dx$

Now, Integrating

$= ( sin\alpha )_{0} ^{\pi }$

= sin π - sin 0

= 0-0

= 0

Final answer:-

$\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha } )d\alpha =0$

5 0

3 years ago