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3 years ago

6

A zip line is setup 150ft in the air, where a person can expect to zip line at a safe declining speed to the ground as they pass

over a body of water, said to be 40 ft in length. Assuming that this cable were stretched tight, where the zip liner is approaching the ground at a 40∘ angle (not the top angle), how many feet of ground would be covered horizontally by the zip liner, not including the body of water? Round to the nearest foot

1 answer:

hichkok12 [17]3 years ago

4 0

Answer:

139 ft

Step-by-step explanation:

So the zip line forms a right triangle. The height of the triangle is 150 ft, and the opposite angle is 40°. The horizontal distance covered by the zip liner can be found with trigonometry, specifically with tangent.

tan 40° = 150 / x

x = 150 / tan 40°

x ≈ 179 feet

But this includes the 40 ft long body of water, so the amount of ground covered is:

179 ft - 40 ft = 139 ft

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elena-14-01-66 [18.8K]

[ Answer ]

$\boxed{2y \ + \ 28}$

[ Explanation ]

4(y + 6) - 2(y - 2)

[Expand] 4(y + 6): 4y + 24

4y + 24 - 2(y - 2)

[Expand] -2(y - 2): -2y + 4

4y + 24 - 2y + 4

[Simplify] 4y + 24 - 2y + 4: 2y + 28

= 2y + 28

$\boxed{[ \ Eclipsed \ ]}$

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A pet store sells goldfish and hermit crabs,

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Answer:

$Cost = \$28$

Step-by-step explanation:

Given

Represent Goldfish with g and hermit crabs with h.

The first statement, we have:

$7g + 3h = 26$

The second statement, we have:

$4g + 5h = 28$

Required

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The equations are:

$7g + 3h = 26$ --- (1)

$4g + 5h = 28$ --- (2)

Make g the subject in (2)

$4g + 5h = 28$

$4g = 28 - 5h$

Divide both sides by 4

$g = \frac{1}{4}(28 - 5h)$

Substitute $\frac{1}{4}(28 - 5h)$ for g in (1)

$7g + 3h = 26$

$7(\frac{1}{4}(28 - 5h)) + 3h = 26$

$\frac{7}{4}(28 - 5h) + 3h = 26$

Multiply through by 4

$4 * \frac{7}{4}(28 - 5h) + 4*3h = 26*4$

$7(28 - 5h) + 4*3h = 26*4$

Open bracket

$196 - 35h + 12h = 104$

$196 -23h = 104$

Collect Like Terms

$-23h = 104-196$

$-23h = -92$

Make h the subject

$h = \frac{-92}{-23}$

$h = \frac{92}{23}$

$h = 4$

Substitute 4 for h in $g = \frac{1}{4}(28 - 5h)$

$g = \frac{1}{4}(28 - 5*4)$

$g = \frac{1}{4}(28 - 20)$

$g = \frac{1}{4}(8)$

$g = 2$

This implies that:

1 goldfish = $2

1 hermit crab = $4

The cost of 6 goldfish and 4 hermit crabs is:

$Cost = 6g + 4h$

$Cost = 6*\$2 + 4*\$4$

$Cost = \$12 + \$16$

$Cost = \$28$

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3 years ago

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a cross between affected or dwarf and normal parent

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a a

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Answer:

Step-by-step explanation:

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2 years ago

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Y_Kistochka [10]

Answer:

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