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Citrus2011 [14]
2 years ago
6

Paul can type 60 words per minute and Jennifer can type 80 words per minute. How does Paul’s typing speed compare to Jennifer’s

Mathematics
2 answers:
Harrizon [31]2 years ago
5 0
Jennifer can type 1/3 faster than Paul
or
Paul can type at 75% the speed of Jennifer

yan [13]2 years ago
4 0
I'm not certain how exactly this question is supposed to be answered. 

If it wants a ratio, Paul and Jennifer's speeds would be in a ratio of 3:4.

It also could be Paul types 20 words per minute slower than Jennifer.

It could be Paul types 33% slower than Jennifer.

Another answer could be Paul's typing speed is 3/4ths of Jennifer's typing speed.

Feel free to ask any further questions.
You might be interested in
Suppose you estimated square root of 12 by averaging a square like rectngle.What would be a reasonable estimation?​
sesenic [268]

Answer:

3.5.

Step-by-step explanation:

3^2 = 9

and 4^2 = 16 so the square root is between 3 and 4.

Take a rectangle 3.4 by 3.6:

the area = 3.4 * 3.6 = 12.24 so an estimate of the square root could be 3.5.

3.5 * 3.5 = 12.25.

5 0
2 years ago
Rewrite in simplest terms: -2(5d-9f)+7f-10(-9f-7d)
Afina-wow [57]

Answer:

= 5 ( 12d + 23f )

Step-by-step explanation:

-2(5d-9f)+7f-10(-9f-7d

Open parenthesis

= -10d + 18f + 7f + 90f + 70d

Collect like terms

= -10d + 70d + 18f + 7f + 90f

= 60d + 115f

Factorise

= 5 ( 12d + 23f )

Therefore,

-2(5d-9f)+7f-10(-9f-7d) in its simplest form is 5 ( 12d + 23f )

4 0
2 years ago
How do I solve this question (19a)?
fredd [130]
Answer i think would be
l-4x+4l
---------
x-1
8 0
3 years ago
Escribe una ecuación de la recta que pasa por el punto (5, –8) con pendiente 5.
Nana76 [90]

Considerando la expresión de una ecuación lineal, la ecuación de la recta que pasa por el punto (5, –8) con pendiente 5 es y= 5x - 33.

<h3>Ecuación lineal</h3>

Una ecuación lineal o línea se puede expresar en la forma y = mx + b

donde

  • x y son coordenadas de un punto.
  • m es la pendiente.
  • b es la ordenada al origen y representa la coordenada del punto donde la línea cruza el eje y.

La ecuación lineal se puede expresar también mediante la ecuación punto-pendiente de la recta, que se plantea si se conoce la pendiente de la recta y cualquiera de sus puntos. Con ello queda determinada la recta, conociendo la pendiente  “m” y un punto  (x1, y1) dado:

y - y1= m(x -x1)

<h3>Ecuación de la recta en este caso</h3>

En este caso, la recta que pasa por el punto (5, –8) con pendiente 5.

Reemplazando en la ecuación punto-pendiente de la recta:

y - (-8)= 5(x -5)

Resolviendo:

y + 8= 5(x -5)

Aplicando propiedad distributiva:

y + 8= 5x - 5×5

y + 8= 5x - 25

Aislando la variable "y":

y= 5x - 25 - 8

<u><em>y= 5x - 33</em></u>

Finalmente, la ecuación de la recta que pasa por el punto (5, –8) con pendiente 5 es y= 5x - 33.

Aprende más sobre ecuación de una recta:

brainly.com/question/25243069

brainly.com/question/19260315

brainly.com/question/24766917

#SPJ1

4 0
1 year ago
A rabbit’s population starts from 2 and doubles every week, how many rabbits will there be in 2
katen-ka-za [31]
14 because you started with 2 and you have 7 weeks in a month. So 2*7=14


6 0
3 years ago
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