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Sindrei [870]
2 years ago
7

OMG IM SO BAD AT THIS HELP KE PLEASE IM BEGGGINNGGGG

Mathematics
1 answer:
vova2212 [387]2 years ago
6 0
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You feature my yt channel I feature yours
MArishka [77]

Answer:

okay

Step-by-step explanation:

we'll try it

6 0
3 years ago
Find the slope and the y−intercept of the line in the graph.
s344n2d4d5 [400]

Answer:

slope = 3/1 or just 3

y intercept = (0, 5)

Step-by-step explanation:

5 0
3 years ago
1/3 of 18 helpp please
MAXImum [283]

Answer:

6

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Please helppp<br> if the slope of a line is 6 and a line is perpendicular to it, what is its slope?
astra-53 [7]

Answer:

-1/6

Step-by-step explanation:

flip the slope

\frac{6}{1}

becomes

\frac{1}{6}

now the slope is going down so it becomes negative

= -1/6

7 0
3 years ago
A quadrilateral WXYZ has vertices W(3, −5), X(1, −3), Y(−1, −5), and Z(1,−7). What are the vertices of r(90, O)(WXYZ)?
VashaNatasha [74]

Given:

A quadrilateral WXYZ has vertices W(3, −5), X(1, −3), Y(−1, −5), and Z(1,−7).

Rule of rotation is r_{(90^\circ, O)}(WXYZ).

To find:

The vertices after rotation.

Solution:

We know that, r_{(90^\circ, O)}(WXYZ) means 90 degrees counterclockwise rotation around the origin.

So, the rule of rotation is defined as

(x,y)\to (-y,x)

Using this rule, we get

W(3,-5)\to W'(5,3)

X(1,-3)\to X'(3,1)

Y(-1,-5)\to Y'(5,-1)

Z(1,-7)\to Z'(7,1)

Therefore, the required vertices after rotation are W'(5,3), X'(3,1),Y'(5,-1) and Z'(7,1).

8 0
3 years ago
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