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saw5 [17]
3 years ago
11

Over 25.5 days, a pond's water level changed by an average of −0.32 centimeter each day. What was the total change in the water

level? Drag and drop the correct answer into the box.
numbers
-10.55
-8.16
10.55
8.16
Mathematics
2 answers:
victus00 [196]3 years ago
4 0

Answer:

 So the water level of pond reduces by 8.16 centimeter over 25.5 days.

Explanation:

 Average change in pond's water level = -0.32 centimeter.

 Duration considered for taking the average of change in pond's water level = 25.5 days.

 Total change in the pond's water level = -0.32*25.5 = -8.16 centimeter

So the water level of pond reduces by 8.16 centimeter over 25.5 days.

melisa1 [442]3 years ago
3 0

Answer:

8.16

Step-by-step explanation:

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a)There is a 4.88% probability that none is concerned that employers are monitoring phone calls.

b)There is a 7.89% probability that all are concerned that employers are monitoring phone calls.

c)There is a 37.23% probability that exactly two are concerned that employers are monitoring phone calls.

Step-by-step explanation:

The binomial probability is the probability of exactly x successes on n repeated trials in an experiment which has two possible outcomes (commonly called a binomial experiment).

It is given by the following formula:

P = C_{n,x}.p^{n}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of a success.

In this problem, a success is being concerned that employers are monitoring phone calls.

53% of adults are concerned that employers are monitoring phone calls, so p = 0.53

(a) Out of four adults, none is concerned that employers are monitoring phone calls.

Four adults, so n = 4.

Is the probability of 0 successes, so x = 0.

P = C_{n,x}.p^{n}.(1-p)^{n-x}

P = C_{4,0}.(0.53)^{0}.(0.47)^{4}

P = 0.0488

There is a 4.88% probability that none is concerned that employers are monitoring phone calls.

(b) Out of four adults, all are concerned that employers are monitoring phone calls.

Four adults, so n = 4.

Is the probability of 4 successes, so x = 4.

P = C_{n,x}.p^{n}.(1-p)^{n-x}

P = C_{4,0}.(0.53)^{4}.(0.47)^{0}

P = 0.0789

There is a 7.89% probability that all are concerned that employers are monitoring phone calls.

(c) Out of four adults, exactly two are concerned that employers are monitoring phone calls.

Four adults, so n = 4.

Is the probability of 4 successes, so x = 2.

P = C_{n,x}.p^{n}.(1-p)^{n-x}

P = C_{4,2}.(0.53)^{2}.(0.47)^{2}

P = 0.3723

There is a 37.23% probability that exactly two are concerned that employers are monitoring phone calls.

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