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Vedmedyk [2.9K]
3 years ago
11

Which situation cannot be represented by the equation 15 + x = 25?

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
5 0

Answer:

the last answer about the jobs

Step-by-step explanation:

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In 1991, the moose population in a park was measured to be 1900. By 1997, the population was measured again to be 3600. If the p
LUCKY_DIMON [66]

Answer:

Since this is a linear (non-exponential) population problem you can just use the standard y=mx+b form of an equation. Where m = (change in population/change in years)

The numbers you were provided state that over the course of 7 years (1998-1991) the population increased by 420 people (4130-3710). So, (420/7) = 60 = m. Assuming that the growth rate for 1990 is the same as 1991. then you would have a starting population of (3710-60) or 3650, that would be your "b" value since at t=0 P(t) = 3650. This yields a final equation of P(t) = 60t +3650. Check the answer at t=1 and you get the population during 1991: 3710.

Step-by-step explanation:

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8 0
2 years ago
Solve equation 3 - 8c = 35
NeTakaya

We would subtact 3 from both sides allowing the equation to simplify to -8c=32

We would then divide both sides by -8 to equal -4

The final answer C=-4

5 0
3 years ago
Rearrange the formula below to make x the subject. α y+1=2x - 10/x+1​
zaharov [31]

Answer:

cross multiplication

x

7 0
2 years ago
Im in Algebra What is <br>2r-6+5r=3-r+7
worty [1.4K]
2r-6+5r=3-r+7

7r-6=10-r

7r+r=10+6

8r=16

r=16/8

r=2
7 0
3 years ago
The sum of 5 consecutive integers is 120. What is the third number in this sequence?
aliina [53]
Ok so

x - the smallest
The other 4 are : x+1, x+2, x+3, x+4
We know that sum is 120
So
x+x+1+x+2+x+3+x+4=120
Combine like terms
5x+10=120
Subtract 10 on both sides
5x=120-10
5x=110
Divide by 5 on both sides
X=22
The third number is x+2 = 22+2=24

3 0
3 years ago
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