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Vedmedyk [2.9K]
3 years ago
11

Which situation cannot be represented by the equation 15 + x = 25?

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
5 0

Answer:

the last answer about the jobs

Step-by-step explanation:

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Solve this x²+8/10 -x = 10/2
AysviL [449]
x^2+\frac{8}{10}-x=\frac{10}{2}\\
x^2-x+\frac{8}{10}-\frac{10}{2}=0\\
x^2-x+\frac{8}{10}-\frac{50}{10}=0\\
x^2-x-\frac{42}{10}=0\\
x^2-x+\frac{1}{4}-\frac{1}{4}-\frac{42}{10}=0\\
(x-\frac{1}{2})^2=\frac{1}{4}+\frac{42}{10}\\
(x-\frac{1}{2})^2=\frac{5}{20}+\frac{84}{20}\\
(x-\frac{1}{2})^2=\frac{89}{20}\\
x-\frac{1}{2}=\sqrt{\frac{89}{20}} \vee x-\frac{1}{2}=-\sqrt{\frac{89}{20}}\\
x=\frac{1}{2}+\frac{\sqrt{89}}{\sqrt{20}} \vee x=\frac{1}{2}-\frac{\sqrt{89}}{\sqrt{20}}\\



x=\frac{1}{2}+\frac{\sqrt{89}}{2\sqrt{5}} \vee x=\frac{1}{2}-\frac{\sqrt{89}}{2\sqrt5}}\\
x=\frac{1}{2}+\frac{\sqrt{445}}{10} \vee x=\frac{1}{2}-\frac{\sqrt{445}}{10}}\\
x=\frac{5+\sqrt{445}}{10} \vee x=\frac{5-\sqrt{445}}{10}}\\
7 0
3 years ago
Your mortgage is $135,400.00 at a 5.25% APR. If you pay $1,500.00 towards the mortgage each month, how much of your second month
Serjik [45]
For the answer to the question above, n the 1st month, the accrued interest is ___ (1/12) * .0525 * 135400 

subtract the interest from the payment to find the change in the principal for the 2nd month 

find the 2nd month's interest and subtract from the payment to find the amount applied to principal. Then that's it!
8 0
3 years ago
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How can I figure out my screentime password.
Deffense [45]

Answer:

Screen record as your parent puts the password in or wipe off your screen and give the parent your phone to put the password in then look at the fingerprint circles and that where each number is, then try all the possible combinations

Step-by-step explanation:

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2 years ago
What are the values of a and b
nikdorinn [45]
A= 58°B= 83° because you add the straight angle which is 90 plus the other number and subtract it by 180 because a triangle has 180°
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3 years ago
When a bush was first planted in a garden, it was 12 inches tall. After two weeks, it was 120% as tall as when it was first plan
e-lub [12.9K]

Answer:

The bush after the two weeks was 14.4 inches tall

Step-by-step explanation:

Let

x ----> bush height after two weeks

we know that

120\%=120/100=1.20

The bush height after two weeks is equal to multiply the height when it was first planted by 1.20

so

x=1.20(12)=14.4\ in

6 0
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