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brilliants [131]
4 years ago
5

Calculate the pH of an aqueous solution of 16 mL of 0.00046 M HClO4(aq) after dilution to 42 mL.

Chemistry
1 answer:
gavmur [86]4 years ago
8 0
1000cm^{3} of HClO_{4} [/tex] contain 0.00046mol
16<span>cm^{3} of HClO_{4} [/tex] contain  x
                       x = </span>\frac{16cm ^{3}  * 0.00046mol}{1000cm x^{3} }
                       x = 0.00000736mol


M_{1} V_{1} = M_{2} V_{2}
(0.00000736mol)(16cm^{3})= (x) (42cm^{2})&#10;
         x=  \frac{(0.00000736mol) * (16cm^{3}) }{42cm^{3} }
                  =  0.000002803mol


pH= -log [H^{+}]
    = -log (0.000002803cm^{3}
    = 5.55
                                
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