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Licemer1 [7]
3 years ago
15

PLEASE HELP ITS DUE SOON PLEASE ILL GIVE BRAINLIESTTT

Chemistry
1 answer:
Helen [10]3 years ago
4 0

Answer:

b. tendons connected muscles to bone.

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A student is performing an experiment to study thermodynamics. The student mixes citric acid and sodium bicarbonate in a calorim
seraphim [82]

Explanation :

In thermodynamics, a system is region or part of space which is being studied and observed while the surrounding is the region or space around the system which interacts with the system.

Here in the experiment ,system which is observed is reaction or changes when citric acid and sodium bicarbonate are mixed together. And the mixing is carried out in the calorimeter which serves as a surrounding around the system.

The reason behind the using the calorimeter is measure the energy change occurring during the reaction.

5 0
4 years ago
In what way did Rannan make an error in his scientific process? He should not use a systemic process. He should not use his opin
Vikentia [17]

The answer from this questions is the letter

B. He should not use his opinions as evidence.


5 0
3 years ago
Read 2 more answers
PLS HELP
vivado [14]

Answer:

D. All of these.

Explanation:

5 0
3 years ago
Convert 22 ml in to liters
prisoha [69]

Answer:

0.022

Explanation:

milliter (ml) = 1 cubic centimeter (cc)= 0.001 liters (l) = 0.000001 cubic meters (m3).

1 ml = 0.061024 cubic inches (in3) ; 1 in3 = 16.4 ml.

1 ml = 0.000035 cubic feet (ft3); 1 ft3 = 28,317 ml.

1 ml = 2.64 x 10-4 U.S. gallons (gal); 1 gal = 4.55 x 103 ml.

8 0
3 years ago
How many milliliters of 0.125 M FeCl3 are needed to react with an excess of Na2S to produce 3.75 g of Fe2S3 if the percent yield
Katyanochek1 [597]

Answer:

0.912 mL

Explanation:

3 Na2S(aq) + 2 FeCl3(aq) → Fe2S3(s) + 6 NaCl(aq)

FeCl3 is the limiting reactant.

Number of moles of iron III sulphide produced= 3.75g/87.92 g/mol = 0.043 moles

Hence actual yield of Iron III sulphide = 0.043 moles

Theoretical yield of Iron III sulphide = actual yield ×100%/ %yield

Theoretical yield of iron III sulphide= 0.043 ×100/75 = 0.057 moles of Iron III sulphide

From the reaction equation,

2moles of iron III chloride produced 1 mole of iron III sulphide

x moles of iron III chloride, will produce 0.057 of iron III sulphide

x= 2× 0.057= 0.114 moles of iron III chloride

But

Volume= number of moles/ concentration

Volume= 0.114/0.125

Volume= 0.912 mL

4 0
3 years ago
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