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3 years ago

A. The unknown sample was purple in color and was verified to only contain blue and red dyes.

Chemistry

1 answer:

juin [17]3 years ago

7 0

Answer:

Answer:It was Results of the spin

Card Color Green Blue Red

Purple Green, Purple Blue, Purple Red, Purple

Green Green, Green Blue, Green Red, Green

Explanation:

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A student performs a titration on 25.0 mL of 0.500M HCL(aq) which is placed in an Erlenmeyer flask. Two drops of indicator are a

Leviafan [203]

Answer:

The unknown NaOH base has a concentration of 0.636M

Explanation:

Step 1: the balanced equation

NaOH + HCl → NaCl + H2O

This means for 1 mole of NaOH consumed there is 1 mole of HCl needed to produce 1 mole of NaCl and 1 mole of H2O

Step 2: Calculate moles of HCl used

Number of moles = Concentration * volume = 0.5M * 25*10^-3 L =0.0125 moles

Step 3: Calculate moles of NaOH

Since the mole ratio for HCl and NaOH is 1:1 this means we have 0.0125 moles of NaOH for 0.0125 moles of HCl

Step 4: Calculate Concentration of the unknown NaOH base

Concentration = Number of moles / Volume

Volume of NaOH = 24.64-5 =19.64 mL = 0.01964 L

Concentration = 0.0125/0.01964 = 0.636 M

The unknown NaOH base has a concentration of 0.636M

8 0

3 years ago

A particle of mass 2.0 kg moves under the influence of the force F(x)=(-5x^2+7x)~\text{N}F(x)=(−5x 2 +7x) N. If its speed at

Brums [2.3K]

Answer:

The speed of the particle at x = 4.0 m is 13.66 m/s

Explanation:

The work done by this force between the two points above is given by

W = ∫ F dx

W = ∫⁴₋₄ (-5x² + 7x) dx

W = [(-5x³/3) + (7x²/2)]⁴₋₄

W = [(-5(4³)/3) + (7(4²)/2)] - [(-5(-4)³)/3) + (7((-4)²)/2)] = (-50.6667) - (162.6667) = (- 213.33 J)

Kinetic energy at -4.0 m

At this point, v = 20 m/s

K.E = mv²/2 = 2 × 20²/2 = 400 J

To obtain the kinetic energy at 4 m,

We apply the work-energy theorem which mathematically translates to

The work done in moving a particle from one point to another = Change in kinetic energy of the particle between those two points

W = ΔK.E

Work done between x = - 4m and x = 4 m is - 213.33 J

Hence, ΔK.E = -213.33 J

Change in kinetic energy of the particle between x = - 4m and x = 4m is ΔK.E

ΔK.E = (Kinetic energy at x = 4m) - (kinetic energy at x = - 4m)

- 213.33 J = (mv²/2) - 400

mv²/2 = -213.33 + 400 = 186.67 J

2v² = 2 × 186.67

v² = 186.67

v = 13.66 m/s.

5 0

3 years ago

Suppose you are provided with a 30.86 g sample of potassium chlorate to perform this experiment. What is the mass of oxygen you

oee [108]

Answer:

The mass of oxygen is 12.10 g.

Explanation:

The decomposition reaction of potassium chlorate is the following:

2KClO₃(s) → 2KCl(s) + 3O₂(g)

We need to find the number of moles of KClO₃:

$\eta_{KClO_{3}} = \frac{m}{M}$

Where:

m: is the mass = 30.86 g

M: is the molar mass = 122.55 g/mol

$\eta_{KClO_{3}} = \frac{30.86 g}{122.55 g/mol} = 0.252 moles$

Now, we can find the number of moles of O₂ knowing that the ratio between KClO₃ and O₂ is 2:3

$\eta_{O_{2}} = \frac{3}{2}*0.252 moles = 0.378 moles$

Finally, the mass of O₂ is:

$m = 0.378 moles*32 g/mol = 12.10 g$

Therefore, the mass of oxygen is 12.10 g.

I hope it helps you!

6 0

3 years ago

Can someone help me pleasee

Romashka [77]

Answer:

4,1,5,3,2 (from left to right)

8 0

3 years ago

The element that appears farthest to the is written first in the chemical name of a covalent compound.

Mashcka [7]

Answer: left

Explanation: The element that appears farthest to the

✔ left

is written first in the chemical name of a covalent compound.

3 0

2 years ago