Answer:
WLAN's or Wireless LAN Units have 2 main modes of operation
Explanation:
The Two Main modes of Operation are the following
<u>Infrastructure Mode:</u> in this mode the main WLAN unit becomes the main connection point in which all devices are connected to and the main unit provides an internet connection to all the devices connected to it.
<u>Ad Hoc Mode:</u> in this mode devices transfer data from one another back and forth without permission from a base unit.
Some WLAN units will also include 2 extra modes of operation called Bridge and Wireless Distribution System (WDS).
<u>Bridge Mode:</u> this mode allows the base unit to act as an intermediary and bridge two different connection points. Such as bridging a wired connection with a wireless one.
<u>WDS Mode:</u> this mode uses various access points to wirelessly interconnect devices to the internet using repeaters to transmit connections. It can provide internet to both wired and wireless clients.
I hope this answered your question. If you have any more questions feel free to ask away at Brainly.
A(n) access point is a box consisting of a radio receiver/transmitter and antennas that links to a wired network, router, or hub.
<h3>What is an access point?</h3>
An access point is known to be a kind of device that makes a wireless local area network, or WLAN, and it is often done in an office or big building.
Therefore, A(n) access point is a box consisting of a radio receiver/transmitter and antennas that links to a wired network, router, or hub.
Learn more about access point from
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Answer:
a) Speedup gain is 1.428 times.
b) Speedup gain is 1.81 times.
Explanation:
in order to calculate the speedup again of an application that has a 60 percent parallel component using Anklahls Law is speedup which state that:
Where S is the portion of the application that must be performed serially, and N is the number of processing cores.
(a) For N = 2 processing cores, and a 60%, then S = 40% or 0.4
Thus, the speedup is:
Speedup gain is 1.428 times.
(b) For N = 4 processing cores and a 60%, then S = 40% or 0.4
Thus, the speedup is:
Speedup gain is 1.81 times.
It is called Ram in another term for memory :)
