All categories

3 years ago

What is the first step in solving the quadratic equation x^2=9 over 16

Mathematics

1 answer:

nikdorinn [45]3 years ago

3 0

Answer:

"Take the square root of both sides of the equation"

A is correct

Step-by-step explanation:

We are given quadratic equation

We need to solve for x. We have to isolate x here.

Here square on x. So, first we get rid of square.

Taking square root both sides to get rid of square.

For example:

a2=25

sqare a2 = +- sqare 25

x2=9/16 to solve for x

sqare x2 +- sqre 9725

x=+- 3/5

Hence, "Take the square root of both sides of the equation"

You might be interested in

Joshua uses a rule to write the following sequence of numbers 1/6,1/2,5/6,----------,11/2 What rule did Joshua use? What is the

Pani-rosa [81]

Answer: The missing number in the sequence is $\frac{7}{6}$

Step-by-step explanation:

Since we have given that

$\frac{1}{6},\frac{1}{2},\frac{5}{6},----------,\frac{11}{2}$

First term = a= $\frac{1}{6}$

Common difference = d is given by

$d=a_2-a_1\\\\\frac{1}{2}-\frac{1}{6}\\\\=\frac{6-2}{12}\\\\=\frac{4}{12}=\frac{1}{3}\\\\Similarly,\\d=a_3-a_2\\\\=\frac{5}{6}-\frac{1}{2}\\\\=\frac{10-6}{12}\\\\=\frac{4}{12}\\\\=\frac{1}{3}$

Therefore, it forms an arithmetic sequence.

Since, $a_4$ is missing,

So,

$a_4=a+3d\\\\a_4=\frac{1}{6}+3\times \frac{1}{3}\\\\a_4=\frac{1}{6}+1\\\\a_4=\frac{1+6}{6}\\\\a_4=\frac{7}{6}$

Hence, the missing number in the sequence is $\frac{7}{6}$

4 0

3 years ago

Read 2 more answers

A drop of oil measuring 0.23 cubic centimeters is spilled into a lake. The oil spread out into a circular shape having a diamete

Kaylis [27]

To determine the thickness of the film, we assume the shape of the film is in a form of cylinder where the thickness is equal to the height. The volume of a cylinder is expressed as:

V = pi (r^2) h

We calculate as follows:

0.23 = pi (10^2) (h)
h = 0.0007 cm

7 0

3 years ago

Help me with this.. thanks

sveta [45]

Answer:

Attachment 1 :- x = 3/2

Attachment 2 :- m + r = 154°

Step-by-step explanation:

Attachment 1 :-

$9^(^2^-^x^) = 3\\=> 3^2^(^2^-^x^) = 3\\$

As the base 3 is same on both the sides , cancel the base 3 from both left & right side of eqn. After that we will get:-

$2(2 - x) = 1\\=> 2 - x =\frac{1}{2} \\=> x = 2 - \frac{1}{2} = \frac{3}{2}$

Attachment 2 :-

PQR is a straight line . It's given that m + n = 110°

But we know that m + n + r = 180° ..............eqn.1

So substituting the value of m+n in eqn.1 gives :-

m+n+r = 180°

=> r + 110° = 180°

=> r = 180° - 110°

= 70°

It's also given that n+r = 96°

So putting the value of r in the above gives ,

n+r = 96°

=> n + 70° =96°

=> n = 96° - 70°

= 26°

Putting the value of n in eqn.1 gives

m + n = 110°

=> m + 26° = 110°

=> m = 110° - 26°

= 84°

So m + r = 84° + 70° = 154°

3 0

3 years ago

The sum of 2 times a number and -7, added to 5 times the number

Anna007 [38]

Let x be the number
2x - 7 + 5x
=7x-7

6 0

3 years ago

Read 2 more answers

AABC has vertices at A(1, -9), B(8,0), and C(9,-8).

Rainbow [258]

Check the picture below.

$~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{1}~,~\stackrel{y_1}{-9})\qquad B(\stackrel{x_2}{8}~,~\stackrel{y_2}{0}) ~\hfill AB=\sqrt{[ 8- 1]^2 + [ 0- (-9)]^2} \\\\\\ AB=\sqrt{7^2+(0+9)^2}\implies AB=\sqrt{7^2+9^2}\implies \boxed{AB=\sqrt{130}} \\\\[-0.35em] ~\dotfill$

$B(\stackrel{x_1}{8}~,~\stackrel{y_1}{0})\qquad C(\stackrel{x_2}{9}~,~\stackrel{y_2}{-8}) ~\hfill BC=\sqrt{[ 9- 8]^2 + [ -8- 0]^2} \\\\\\ BC=\sqrt{1^2+(-8)^2}\implies \boxed{BC=\sqrt{65}}$

now, we could check for the CA distance, however, we already know that AB ≠ BC, so there's no need.

6 0

2 years ago