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SpyIntel [72]
3 years ago
9

What is the first step in solving the quadratic equation x^2=9 over 16

Mathematics
1 answer:
nikdorinn [45]3 years ago
3 0

Answer:

"Take the square root of both sides of the equation"

A is correct

Step-by-step explanation:

We are given quadratic equation

We need to solve for x. We have to isolate x here.

Here square on x. So, first we get rid of square.

Taking square root both sides to get rid of square.

For example:

a2=25

sqare a2  = +- sqare 25

x2=9/16 to solve for x

sqare x2 +- sqre 9725

x=+- 3/5

Hence, "Take the square root of both sides of the equation"

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Y = -4x + 3<br> 8x + 2y = 8<br> Solve by using elimination.
ValentinkaMS [17]

Answer:

The equations are not compatible

Step-by-step explanation:

y = -4x + 3

8x + 2y = 8

substitute for y:

8x + 2(-4x + 3) = 8

simplify:

8x - 8x + 6 = 8

6 ≠ 8

3 0
2 years ago
Sort the ratios listed at the right into bins so that equivalent ratios are grouped together:
sesenic [268]
What are the ratios and what are the different bins
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3 years ago
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Consider the given density curve.
alisha [4.7K]

The Median of the density is -6.

An illustration of a numerical distribution with continuous results is a density curve. A density curve is, in other words, the graph of a continuous distribution. This implies that density curves can represent continuous quantities like time and weight rather than discrete events like rolling a die (which would be discrete). As seen by the bell-shaped "normal distribution," density curves either lie above or on a horizontal line (one of the most common density curves).

It is clearly visible from the uniform density curve given in the question that the median of the population density is  -6.
Because the area to the left and right of the density curve is the same.

Hence, the Median of density is -6.

Learn more about density curves here-

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2 years ago
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The management of a relatively new social networking website named BooglePlus is conducting a pilot study comparing use of its o
zavuch27 [327]

Answer:

0.0623 ± ( 2.056 )( 0.0224 ) can be used to compute a 95% confidence interval for the slope of the population regression line of y on x

Step-by-step explanation:

Given the data in the question;

sample size n = 28

slope of the least squares regression line of y on x or sample estimate = 0.0623

standard error = 0.0224

95% confidence interval

level of significance ∝ = 1 - 95% = 1 - 0.95 = 0.05

degree of freedom df = n - 2 = 28 - 2 = 26

∴ the equation will be;

⇒ sample estimate ± ( t-test) ( standard error )

⇒ sample estimate ± ( t_{\alpha /2, df) ( standard error )

⇒ sample estimate ± ( t_{0.05 /2, 26) ( standard error )

⇒ sample estimate ± ( t_{0.025, 26) ( standard error )

{ from t table; ( t_{0.025, 26) = 2.055529 = 2.056

so we substitute

⇒ 0.0623 ± ( 2.056 )( 0.0224 )

Therefore, 0.0623 ± ( 2.056 )( 0.0224 ) can be used to compute a 95% confidence interval for the slope of the population regression line of y on x

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3 years ago
A school is buying 35 new computers. If the price of each computer is $1,099,
dolphi86 [110]

Answer:

$38,465

Step-by-step explanation:

35 x 1,099 = 38,465

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