5+3(q-4)=2(q+1) I don’t understand how to solve this question
1 answer:
Answer:
q = 9
Step-by-step explanation:
5 + 3(q - 4) = 2(q + 1)
To solve, you need to get q by itself on one side.
5 + 3q - 12 = 2q + 2 --- distribute the multipliers next to the parenthesis
3q - 7 = 2q + 2 --- combine like terms
q - 7 = 2 --- subtract 2q from both sides
q = 9 --- add 7 to both sides
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hope helps with the first the rest i cant read its not clear.
<h3>Solution:</h3>
- Given, side (a) = x+3
- We know, surface area of a cube = 6a^2
- Therefore, the surface area of the cube
<h3> </h3><h3>
</h3><h3>Answer:</h3>
The answer is
<h3>Hope it helps.</h3>
Sorry for delay
Answer:
A
Step-by-step explanation:
i stands for square root of negative 1. If you multiple i and square root of 23 you will end up with the original
Answer:
Step-by-step explanation:
Sorry i’m not sure have a good day!
